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Sati [7]
4 years ago
6

-3(1-8x-2y) in standard form

Mathematics
1 answer:
madreJ [45]4 years ago
7 0
In standard form, -3(1-8x-2y) is:
DISTRIBUTIVE PROPERTY: 3+24x+6y
ANSWER: 24x+6y-3
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X/5 = 25<br> i need help
Aleksandr-060686 [28]

x = 125

Multiply both sides by 5:

x/5 X 5 = x

and

25 X 5 = 125

so you're left with:

x = 125

Hope this helps

5 0
3 years ago
Read 2 more answers
a. it is a multiple of 3,b. is greater then 100 ,c. it is not even, d.all digits are odd. whats the number?
uranmaximum [27]

Answer:

333.

Step-by-step explanation:

3•111=333

333>100

All the digits are odd...


4 0
3 years ago
The sum of two numbers is 32 and their difference is 8 what are the two numbers
Likurg_2 [28]
A+b=32
a-b=8

let's subtract bottom equation from the top:

a+b-(a-b)=32-8
2b=24
b=12

Then a=20
4 0
3 years ago
A chip used in the production of particleboard (Question 4) has a 15% chance of containing excessive bark. What is the probabili
salantis [7]

Answer:

0.2

Step-by-step explanation:

Given that:

P(particleboard with excessive bark) = 0.15

The P(that particleboard do not have excessive bark) = 1 - 0.15

i.e the population proportion number of success p = 0.85

The sample size (n) is given to be = 1000

To find the P(X ≥ 860)

Since the sample size is large, we will apply the normal approximation of binomial distribution to treat this question.

The population mean \mu = n \times p

\mu = 1000 \times 0.85

\mu =850

The population standard deviation \sigma = \sqrt{n*p(1-p)

\sigma = \sqrt{1000*0.85*(1-0.85)}

\sigma = \sqrt{1000*0.85*(0.15)}

\sigma = \sqrt{127.5}

\sigma = 11.2916

Let X be the random variable which obeys a normal distribution;

Then;

P(X \ge 860) = P(Z\ge \dfrac{x- \mu}{\sigma})

P(X \ge 860) = P(Z\ge \dfrac{860- 850}{11.2916})

P(X \ge 860) = P(Z\ge \dfrac{10}{11.2916})

P(X ≥ 860) = P(Z ≥ 0.8856)

P(X ≥ 860) = 1 - P(Z ≤ 0.8856)

From  z table

P(X ≥ 860) = 1 - 0.8122

P(X ≥ 860) = 0.1878

P(X ≥ 860) \simeq 0.2

Thus, the probability of having more than 860 bark-free chips in a batch of 1,000 = 0.2

6 0
3 years ago
A fair coin is tossed three time sin succession. the set of equally likely outcomes is {hhh,hht,hth,thh,htt,tht,tth,ttt}. find t
n200080 [17]
There are 8 possible outcomes so that means the probability will have a denominator of 8.

Now, there is only one of the eight outcomes that has zero tails.

Therefore the probability of getting zero tails after tossing a fair coin three times in succession is

​
\frac{1}{8}
6 0
3 years ago
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