All categories

3 years ago

-3(1-8x-2y) in standard form

Mathematics

1 answer:

madreJ [45]3 years ago

7 0

In standard form, -3(1-8x-2y) is:
DISTRIBUTIVE PROPERTY: 3+24x+6y
ANSWER: 24x+6y-3

You might be interested in

Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago

Which function has a vertex at ( 2 , -5 )?

Mice21 [21]

The answer is C) y= |x-2| -5

3 0

2 years ago

SOMEONE PLS HELP ME WITH ASAP

Levart [38]

Answer:

area of trapezium in terms of x=1/2*x(x+3+x+1)

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

A _______has one endpoint line or ray

Nikolay [14]

Answer:

Ray.

Step-by-step explanation:

Lines have no endpoints, while rays have 1 endpoint (:

7 0

2 years ago

HELP ME PLZ ILL GIVE U EXTRA POINTS

likoan [24]

Answer:

10 32 -9

10 -13 18

-9 -8 11

hope this helps

6 0

3 years ago