Answer:
<h2>16c² + 32cd + 16d²</h2>
Step-by-step explanation:
Area = (4c + 4d)×(4c + 4d)
= 16c² + 16cd + 16dc + 16d²
= 16c² + 32cd + 16d²
None of those answers are correct sadly.
Hello!
So, according to the problem, the heart rate of a bear during hibernation is 
its original amount.
So we can write an equation to help us understand this.
of sr = 28
We can use inverse to make this easier to solve. 2 × 28 = sr.
So, in simple form, we multiply.
28 × 2 = 56
Our final answer would be:
A bears heart rate during the summer would be 56 beats per minutes.
<em>waffletowne. </em>
simple interest formulae = PRT/100
where
p stands for percentage (2%)
r stands for rate ( 900)
t stands for time (2 years )
2×900×2/100
=3600/100
=36
Answer:
1). The constant of variation is 7
2). w = 6 for the given values of x and y
Step-by-step explanation:
"Varies jointly" tells us that y is a direct result of a mathematic operation involving x and w. We will assume y is directly prorportional to x and w, in the sense that we can find a multiplicative relationship of the form y=Kxw, where K is the constant of variation.
We are given one data point: y=-42 where x is 2 and w is -3. Let's put those values into our trrial expression:
y=Kxw
-42=K(2)(-3)
-42 = -6K
K = 7
<h2>The expression becames <u>
y = 7xw</u></h2>
The constant of variation is 7.
The value of w for y=3 and x=(1/14) would be:
y=7xw
3 = 7*(1/14)*w
3 = (1/2)*w
<h2><u>
w = 6</u></h2>
