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Sauron [17]
3 years ago
10

Select the statement that describes this expression: fraction 1 over 2 x (734 − 246).

Mathematics
2 answers:
vodomira [7]3 years ago
3 0

Answer:

244

Step-by-step explanation:

fraction fraction 1/2 the quotient of 734 and 246

Mademuasel [1]3 years ago
3 0

Answer:

Its D

Step-by-step explanation:

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Please, it’s due tonight and I suck at proofs:((
Slav-nsk [51]

Answer:

The question ?

Step-by-step explanation:

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Add 34+(−212) using the number line. Select the location on the number line to plot the sum.
Korvikt [17]

Answer:

Answer is explained below in the explanation section.

Step-by-step explanation:

Solution:

For this question, we need to have a number line, we can not make the number line here. As it will be very long. Instead, I have attached a number line from -11 to +11 for your understanding and explained it below. Please refer to the attachment below for the number line.

Number Line:

A number line is a line which contains all the numbers from negative infinity to positive infinity divided by a single number zero. It has two sides, left hand side and right hand side. A side left to zero contains all the negative numbers and a side right to 0 contains, all the positive numbers.

So,

We are asked to add 34 in (-212), we will get 178 but with the negative sign, and it will lie on the left hand side of the number line.

SO,

34 + (-212) = 34 - 212 = -178

Hence,

Our sum which is 178 will lie on the left hand side of the number line.

4 0
3 years ago
An object is launched from ground level with an initial velocity of 120 meters per second. For how long is the object at or abov
babunello [35]

Answer:

D) 14 seconds

Step-by-step explanation:

First we will plug 500 in for y:

500 = -4.9t² + 120t

We want to set this equal to 0 in order to solve it; to do this, subtract 500 from each side:

500-500 = -4.9t² + 120t - 500

0 = -4.9t²+120t-500

Our values for a, b and c are:

a = -4.9; b = 120; c = -500

We will use the quadratic formula to solve this.  This will give us the two times that the object is at exactly 500 meters.  The difference between these two times will tell us when the object is at or above 500 meters.

The quadratic formula is:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Using our values for a, b and c,

x=\frac{-120\pm \sqrt{120^2-4(-4.9)(-500)}}{2(-4.9)}\\\\=\frac{-120\pm \sqrt{14400-9800}}{-9.8}\\\\=\frac{-120\pm \sqrt{4600}}{-9.8}\\\\=\frac{-120\pm 67.8233}{-9.8}\\\\=\frac{-120+67.8233}{-9.8}\text{ or }\frac{-120-67.8233}{-9.8}\\\\=\frac{-57.1767}{-9.8}\text{ or }\frac{-187.8233}{-9.8}\\\\=5.3242\text{ or }19.1656

The two times the object is at exactly 500 meters above the ground are at 5 seconds and 19 seconds.  This means the amount of time it is at or above 500 meters is

19-5 = 14 seconds.

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