-13<w because 9*w and 9*3 = 90>-9w-27 then add 27 and get 117>-9w then divide and get -13<w
Answer:
The product of the other two zeros is c
Step-by-step explanation:
Let α, β and γ be the zeros of the polynomial x³ + ax² + bx + c. Since one of the zeros is -1, therefore let γ = -1. Hence:
sum of the roots = α + β + γ = -a
-1 + β + γ = -a
β + γ = -a + 1
αβ + αγ + βγ = b
-1(β) + (-1)γ + βγ = b
-β -γ + βγ = b
Also, the product of the zeros is equal to -c, hence:
αβγ = -c
-1(βγ) = -c
βγ = c
Hence the product of the other two zeros is c
Answer:
its just 9
Step-by-step explanation:
Divide: 3 : 1 / 3 = 3 / 1 · 3 / 1 = 3 · 3 / 1 · 1 = 9 / 1 = 9 Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator,
Answer:
C=47
B=133
Step-by-step explanation:
For this case we have the following function:
A (t) = P (1 + r / n) ^ nt
Substituting values we have:
A (4) = 500 * (1 + 0.09 / 1) ^ (1 * (4))
A (4) = 705.790805
Rounding we have:
A (4) = 705.79
Answer:
The answer for this case is given by:
A (4) = 705.79
option A
