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4 years ago

Solve the equation -11x Squared +1331=0

Mathematics

1 answer:

frozen [14]4 years ago

7 0

I hope this is right but the answer i got is x squared = 121

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Please solve the inequality: -15< or equal to 5(3p-2) and is < and equal to 20

Levart [38]

It has been awhile since I worked with in qualities but I got the answer, -1/3 < or equal to p < or equal to 2. I multiplied the 5 in the middle of the equation with what's in parentheses to get 15p - 10, then I added 10 to both outer sides of the equation and got -5 < or equal to 15p < or equal to 30. Then lastly I divided 15 by -5 and 30! I hope that's right.. I'm sorry if it isn't!

5 0

3 years ago

Guy's y'all plzz answer this who knows about it...and also exam is near

Yanka [14]

Answer:

Step-by-step explanation:

Okay so I will explain the first one.

2 to the power of 4 = 2x2x2x2

2 to the power of 6 = 2x2x2x2x2x2

2 to the power of 4 = 2x2x2x2

2^4 = 16

2^6 = 64

When you are multiplying powers you add.

When you subtract you takeaway.

So you would do

4+6+4

= 14

Meaning 2 to the power of 14

2 $x^{14}$

So what is 2 to the power of 14.

You would do

2x2x2x2x2x2x2x2x2x2x2x2x2x2

The answer is 16384

You can also use a calculator

GOOD LUCK FOR YOUR TEST!

7 0

3 years ago

Convert 0.000007914 to scientific notation

Black_prince [1.1K]

7.914 * 10^-6 is 0.000007914 in scientific notation

4 0

3 years ago

Laboratory tests show that the lives of

defon

Answer:

34%

Step-by-step explanation:

LammettHash is right just take it as a whole number (for those of you using acellus)

6 0

2 years ago

Plot the points A(9, 11) and B(–3, –5). Find midpoint M of AB. Then show that AM = MB and AM + MB =AB

Alex_Xolod [135]

Answer:

The midpoint is (3, 3).

Step-by-step explanation:

We are given the two points A(9, 11) and B(-3, -5).

The midpoint is given by:

$\displaystyle M=\Big(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\Big)$

So:

$\displaystyle M = \Big( \frac{9+(-3) }{2}, \frac{ 11+(-5) }{2} \Big) = (3,3)$

The midpoint is (3, 3).

We want to show that AM = MB.

We can use the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

The distance between A(9, 11) and M(3, 3) will then be:

$AM=\sqrt{(9-3)^2+(11-3)^2}=\sqrt{6^2+8^2}=\sqrt{100}=10$

And the distance between B(-3, -5) and M(3, 3) will be:

$MB = \sqrt{ (3-(-3))^2 + (3-(-5))^2 } = \sqrt{(6)^2+(8)^2} = \sqrt{ 100 } = 10$

So, AM = MB = 10.

Since AM = MB = 10, AM + MB = 10 + 10 = 20.

So, we want to prove that AB = 20.

By the distance formula:

$AB=\sqrt{(9-(-3))^2+(11-(-5))^2}=\sqrt{12^2+16^2}}=\sqrt{400}=20\stackrel{\checkmark}{=}20$

4 0

3 years ago