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iogann1982 [59]
3 years ago
11

Wee-Mobile is offering a cell phone family plan for its users. The breakdown of the cost of the plan per month is given below.

Mathematics
1 answer:
Stells [14]3 years ago
8 0

The total cost for a 6-month plan for n lines is represented by the equation:

Cost = 660n + 100

This equation is in the slope intercept form. The coefficient of n represents the slope here.

In the given scenario the slope can be interpreted as the total variable cost for one line for a period of 6 months.

The variable costs are associated with a line are:

1) Unlimited data cost ($40 per month). So for 6 months this cost will be $240

2) Unlimited Call cost ($10 per month). So for 6 months this cost will be $60

3) Unlimited Text Message Cost ($10 per month). For 6 months this cost will be $60.

4) Cost of Phone ($300 per line)

Adding these costs up we get: 240 + 60 + 60 + 300 = $660

Thus, 660 represents the total cost per line for unlimited data, calls, text message and one phone for 6 months. Therefore, option A gives the correct answer.

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Determine the decibel values of thermal noise power (N) and thermal noise power density (No) given the following: T=292 degrees
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Answer: d. None of the above are correct.

Step-by-step explanation: Noise is a superfluous random alteration in an eletrical signal. There are different types of noises created by different devices and process. Thermal noise is one of them. It is unavoidable because is created by the agitation of the charge carriers, due to temperature, inside an eletrical conductor at equilibrium and is present in all eletrical circuits.

The formula to find the thermal noise power (N) is: N = k_{b}.T.B, where:

k_{b} is Boltzmann constant (1.38.10^{-23}J/K);

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Calculating the thermal noise power:

N = 1.38.10^{-23}·292·40

N = 16118.4.10^{-23} dBm

The thermal noise power [N] = 16118.4.10^{-23} dBm

Noise power density or simply Noise density (N₀) is the noise power per unit of bandwith and its SI is watts per hertz.

For thermal noise, N₀ = kT, where

<em>k </em>is the Boltzmann constant in J/K;

T is the receiver system noise temperature in K;

N₀ = 1.38.10^{-23} . 292

N₀ = 402.96.10^{-23} W/Hz

The thermal noise power density [N₀] = 402.96.10^{-23} W/Hz

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