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iogann1982 [59]
3 years ago
11

Wee-Mobile is offering a cell phone family plan for its users. The breakdown of the cost of the plan per month is given below.

Mathematics
1 answer:
Stells [14]3 years ago
8 0

The total cost for a 6-month plan for n lines is represented by the equation:

Cost = 660n + 100

This equation is in the slope intercept form. The coefficient of n represents the slope here.

In the given scenario the slope can be interpreted as the total variable cost for one line for a period of 6 months.

The variable costs are associated with a line are:

1) Unlimited data cost ($40 per month). So for 6 months this cost will be $240

2) Unlimited Call cost ($10 per month). So for 6 months this cost will be $60

3) Unlimited Text Message Cost ($10 per month). For 6 months this cost will be $60.

4) Cost of Phone ($300 per line)

Adding these costs up we get: 240 + 60 + 60 + 300 = $660

Thus, 660 represents the total cost per line for unlimited data, calls, text message and one phone for 6 months. Therefore, option A gives the correct answer.

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HELP!!! RST has vertices R(-3, - 1), S(0,3), and t(3,0). What type of triangle is RST?
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<h3>Answer: C) scalene</h3>

======================================================

Explanation:

Use the distance formula to calculate the distance from R to S. This is identical to the length of segment RS.

R = (x_1,y_1) = (-3,-1) \text{ and } S = (x_2, y_2) = (0,3)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-3-0)^2 + (-1-3)^2}\\\\d = \sqrt{(-3)^2 + (-4)^2}\\\\d = \sqrt{9 + 16}\\\\d = \sqrt{25}\\\\d = 5\\\\

Segment RS is exactly 5 units long.

-----------------------

Repeat similar steps to find the length of segment ST

S = (x_1,y_1) = (0,3) \text{ and } T = (x_2, y_2) = (3,0)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(0-3)^2 + (3-0)^2}\\\\d = \sqrt{(-3)^2 + (3)^2}\\\\d = \sqrt{9 + 9}\\\\d = \sqrt{18}\\\\d \approx 4.2426\\\\

ST is roughly 4.2426 units long.

------------------------

Lastly, let's calculate the length of segment TR.

T = (x_1,y_1) = (3,0) \text{ and } R = (x_2, y_2) = (-3,-1)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-(-3))^2 + (0-(-1))^2}\\\\d = \sqrt{(3+3)^2 + (0+1)^2}\\\\d = \sqrt{(6)^2 + (1)^2}\\\\d = \sqrt{36 + 1}\\\\d = \sqrt{37}\\\\d \approx 6.0828\\\\

TR is about 6.0828 units long.

------------------------

Summary of the segment lengths:

  • RS = 5 exactly
  • ST = 4.2426 approximately
  • TR = 6.0828 approximately

The three sides are different lengths.

Therefore, the triangle is <u>scalene</u>.

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