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3 years ago

Help pls I need this done by tmr

Mathematics

1 answer:

Ivanshal [37]3 years ago

8 0

2 is not divisible
3 is not divisible
4 is not divisible
5 is not divisible
6 is not divisible
9 is not divisible
And 10 is not divisible

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Given each of the following areas, what would be the radius of each circle? a. A = 530.66 m2 b. A = 907.46 sq. ft. c. A = 379.94

ra1l [238]

Area for a circle is $A= \pi r^2$ . We will fill in each area and then solve for the radius. $530.66m^2= \pi r^2$ and $\frac{530.66m^2}{3.14}=r^2$ . ∴ $169=r^2$ and r = 13. For b, $907.46ft^2= \pi r^2$ and $\frac{907.46ft^2}{3.14}=r^2$ . $289=r^2$ , ∴ r = 17. For c, $379.94mi^2= \pi r^2$ , and $\frac{379.94mi^2}{3.14}=r^2$ . ∴, $121=r^2$ and r = 11. For d, $1962.5cm^2= \pi r^2$ , and $\frac{1962.5cm^2}{3.14}=r^2$ . ∴, $625=r^2$ so r = 25. And there you have it!

3 0

3 years ago

11 4/7 as an improper fraction

ivolga24 [154]

Answer:

114 is an improper fraction as numerator 11 is greater than 4, the denominator. Step 2: We divide 11 by 4, and get 2 as a quotient and 3 as a remainder which is written as proper fraction 34.

3 0

3 years ago

Read 2 more answers

Diagram below shows the curve of a quadratic function

uranmaximum [27]

Answer:

q = -8, k = 2.

r = -6.

Step-by-step explanation:

f(x) = (x - p)^2 + q

This is the vertex form of a quadratic where the vertex is at the point (p, q).

Now the x intercepts are at -6 and 2 and the curve is symmetrical about the line x = p.

The value of p is the midpoint of -6 and 2 which is (-6+2) / 2 = -2.

So we have:

f(x) = 1/2(x - -2)^2 + q

f(x) = 1/2(x + 2)^2 + q

Now the graph passes through the point (2, 0) , where it intersects the x axis, therefore, substituting x = 2 and f(x) = 0:

0 = 1/2(2 + 2)^2 + q

0 = 1/2*16 + q

0 = 8 + q

q = -8.

Now convert this to standard form to find k:

f(x) = 1/2(x + 2)^2 - 8

f(x) = 1/2(x^2 + 4x + 4) - 8

f(x) = 1/2x^2 + 2x + 2 - 8

f(x) = 1/2x^2 + 2x - 6

So k = 2.

The r is the y coordinate when x = 0.

so r = 1/2(0+2)^2 - 8

= -6.

3 0

3 years ago

Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by:

$z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811$

The confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

4 0

3 years ago

Solve the following system of equations: x - 2y = 14 x + 3y = 9

Margarita [4]

Solve your system of equations step by step.

x−2y=14;x+3y=9

Solve x−2y=14 for x:

x−2y+2y=14+2y (Add 2y to both sides)

x=2y+14

Substitute (2y+14) for x in x+3y=9:

x+3y=9

2y+14+3y=9

5y+14=9(Simplify both sides of the equation)

5y+14+−14=9+−14 (Add -14 to both sides)

5y=−5

5y5=−55 (Divide both sides by 5)

y=−1

Substitute (−1) for y in x=2y+14:

x=2y+14

x=(2)(−1)+14

x=12(Simplify both sides of the equation)

So,

y=-1
x=12

Answer is C)

3 0

3 years ago