I think K=1.123
you have to find by how much it's increasing, think of 6(1/2) times WHAT equals 7(1/3)
6(1/2)a=7(1/3)
a=1.123
That means each side will be the same times 1.123
x=4.492
you can round that to 4.49 or 4.5 or 5

3 0

3 years ago

Find the measure of the largest angle in ABC if a = 12, b = 8 and c = 13.

Papessa [141]

Answer:

$C=78.28^{\circ \:}$

Step-by-step explanation:

We are given a triangle

whose sides are

a=12

b=8

c=13

Since, c is largest among them

So, angle C must be largest angle

we can find angle C

we can use law of cosine formula

$cos(C)=\frac{a^2+b^2-c^2}{2ab}$

now, we can plug values

$cos(C)=\frac{12^2+8^2-13^2}{2\times 12\times 8}$

$cos(C)=\frac{13}{64}$

now, we can find angle

we get

$C=78.28^{\circ \:}$

5 0

2 years ago

The midpoint of PQ is M(2,-3). One endpoint is P(4,1). Find the coordinates of endpoint Q.

kupik [55]

Q (0,-7)

Hope this helps

3 0

3 years ago