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erastovalidia [21]
2 years ago
7

If EH = w and GH = 4w - 51, what is GH?

Mathematics
1 answer:
Arturiano [62]2 years ago
3 0

Answer:

Step-by-step explanation:

EH=w

then it is as simple as pluggin in

gh=4(eh)-51

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Carla has a dog walking service and makes $9 for every day works walking dogs. One week, she was sick and could only walk the do
Alexeev081 [22]

Answer: 18+36=$54

Step-by-step explanation: The first week that she was sick, she walked dogs 2 times, meaning she would earn $18 (2*9=18).

The second week when she walked dogs 4 times, she'd earn $36 (4*9=36).

5 0
3 years ago
See question in attached photo.<br>Answer question 4b and 5c​
sdas [7]

9514 1404 393

Answer:

  4b: 8.6 m/s²; 1.3×10^5 N; 2.1×10^4 N decrease

  5c: -1.6×10^12 J; -1.6×10^12 J

Step-by-step explanation:

<h3>4b</h3>

i) The acceleration due to gravity is inversely proportional to the square of the distance between the objects. The distance to the shuttle is ...

  1 + (5×10^5)/(6.4×10^5) = 69/64 . . . times the radius of the earth

Then the acceleration due to gravity at the height of the space shuttle is about ...

  (10 m/s²)(64/69)² ≈ 8.6 m/s²

__

ii) The weight of the space shuttle at that height is about ...

  F = ma = (15000 kg)(8.6 m/s²) ≈ 1.3×10^5 N

__

iii) The loss of weight will be ...

  ΔF = m(a1 -a0) = (15000 kg)(10 m/s² -8.6 m/s²)

  = 1.5×10^4×1.4 N = 2.1×10^4 N

____

<h3>5c</h3>

i) The gravitational potential energy is given by ...

  U = -GMm/r

where M and m are the mass of the earth and the rocket, respectively.

  U = -(6.67×10^-11)(6.0×10^24)(2.5×10^4)/(6.4×10^6) ≈ -1.6×10^12 J

__

ii) At a height of 3×10^4 m, the denominator in the above expression changes from 6.4×10^6 to 6.43×10^6. This changes the gravitational potential energy by a factor of 6.4/6.43 to -1.6×10^12 J

(Note: we're carrying only 2 significant figures in the result in accordance with the rules for precision in such calculations. The change is noticeable at the level of the 4th significant figure, less than 1/2%.)

4 0
2 years ago
Natalie had a job after school. She worked 25 hours a week and got paid $6.25 an hour. How much money would she earn for two wee
erastovalidia [21]

Answer:

312.5

Step-by-step explanation:

25 x 2, for two weeks of work = 50

50 x 6.25 = 312.5

6 0
3 years ago
Read 2 more answers
Jocelyn purchased a new car in 2000 for $16, 100. The value of the car has
Maslowich
I think its 900 i’m not sure
7 0
2 years ago
I need help for this, thanks
gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

---------------------------------------------------------------------------------------

(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

5 0
3 years ago
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