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mr Goodwill [35]
3 years ago
12

You've fallen into my trap! justin shouts, laughing like the madman he is. the mouse he captured stares back at him indifferentl

y as it munches on a piece of cheese at the bottom of a box whose base measures 1 2 12 cm12, space, c, m by 1 2 12 cm12, space, c, m.
Mathematics
2 answers:
fgiga [73]3 years ago
3 0

Answer:

all of the sides are 18 units

Step-by-step explanation:

Yuri [45]3 years ago
3 0

Answer:

18

Step-by-step explanation:

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Boulder, Cobble, Pebble, Sand, Silt, Clay
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3 years ago
Let u,v,wu,v,w be three linearly independent vectors in R7R7. Determine a value of kk, k=k= , so that the set S={u−3v,v−2w,w−ku}
11Alexandr11 [23.1K]

Answer:

1/6

Step-by-step explanation:

For a set of vectors a, b and c to be linearly dependent, the linear combination of the set of vectors must be zero.

C1a + C2b + C3c = 0

From the question, we are given the set S={u−3v,v−2w,w−ku}, the corresponding vectors are a(0, -3, 1), b(-2,1,0) and c(1,0,-k)

The values in parenthesis are the ccoefficients of w, v and u respectively.

On writing this vector as a linear combination, we will have;

C1(0, -3, 1) + C2(-2,1,0) + C3(1,0,-k) = (0,0,0)

0-2C2+C3 = 0........ 1

-3C1+C2 = 0 ........... 2

C1-kC3 = 0 ….......... 3

From equation 2, 3C1 = C2

Substituting into 1, -2(3C1)+C3 = 0

-6C1+C3 = 0

-6C1 = -C3

6C1 = C3.…..4

Substitute 4 into 3 to have

C1-k(6C1) = 0

C1 = k6C1

6k = 1

k = 1/6

Hence the value of k for the set of vectors to be linearly dependent is 1/6

6 0
3 years ago
What is the volume of a cylinder with base radius 2 and height 6?
DaniilM [7]

Answer:

75.4

Step-by-step explanation:

just follow the formula.

6 0
3 years ago
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