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tangare [24]
3 years ago
15

BRAINLIESTTTT ASAP!!! PLEASE HELP ME :)

Chemistry
2 answers:
UNO [17]3 years ago
6 0

Answer:

Decomposition and redox  

Explanation:

2Ni₂O₃ ⟶ 4Ni + 3 O₂

This can be classed as a decomposition reaction, because a compound is decomposing into simpler substances.

It can also be classed as a redox reaction. The oxidation number of Ni decreases (reduction) from +3 in Ni₂O₃ to 0 in Ni, while the oxidation number of O increases (oxidation) from -2 in Ni₂O₃ to 0 in O₂.

Among the many types of reactions are:

  • Combination
  • Decomposition
  • Single displacement
  • Double displacement
  • Reduction-oxidation
  • Precipitation

uranmaximum [27]3 years ago
5 0

Answer:

I think its Decomposition and redox  

Explanation:

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Can someone help me answer this question
Softa [21]

Answer:

p= 1

e= 1

n= 0

predicted charge= +1

name of ion= Hydride

5 0
3 years ago
Use tabulated half-cell potentials to calculate ΔG∘rxn for each of the following reactions at 25 ∘C.
Ilya [14]

Answer:- \Delta G^0 for the reaction is -58 kJ/mol.

Solution:- Oxidation half reaction taking place at the anode is--

3Sn(s)\rightarrow 3Sn^2^+(aq) + 6e^- E^0 = 0.14 V

Reduction half equation taking place at the cathode is---

2Fe^3^+(aq) + 6e^-\rightarrow 2Fe(s) E^0 = -0.04V

E^0 for the cell = E_(reduction) + E_(oxidation)

E^0 for the cell = -0.04V + 0.14V = 0.10V

Now we could easily calculate \Delta G^0 by using the below formula--

\Delta G^0 = -nFE^0

where n is the number of electrons transferred in the over all reaction. Looking at two half equations the value of n is 6.

F is Farady constant and it's value is 96500 C/mol.

Plugging in the values in the formula...

\Delta G^0 = -(6)(96500)(0.10)

\Delta G^0 = -57900 J

Since, 1000 J = 1 kJ

So, \Delta G^0 = -58 kJ/mol

7 0
3 years ago
Which quanity is equal to 50 kilojoules?
likoan [24]
500 J (I've had the same question before so I know what answers there are... lol)
8 0
3 years ago
Can someone help me with this?
amm1812

Answer:

dnaq tester

Explanation:

5 0
4 years ago
When a solute is added to a solution why does it remain homogeneous?
Olenka [21]
<h3>Answer:</h3>

                 When a solute is added to a solution, it remains homogeneous because the solute is soluble in given solvent.

<h3>Explanation:</h3>

                         Homogeneous mixtures, also called true solutions are those mixtures in which the components proportions are same throughout in any given sample. For example, the mixture of table salt (NaCl) and water. When the solution is unsaturated and further NaCl is added to it, it will dissolve the NaCl because the saturation point is still not reached. Remember, as "<em>Like Dissolves Like</em>" NaCl being polar in nature will interact with water molecules and will dissociate into Na⁺ and Cl⁻ ions surrounded by δ- O and δ+ H atoms of water molecules.

<h3>Conclusion:</h3>

                  In order to form a Homogeneous mixture the solution must be unsaturated, solvent must have affinity for incoming solute particles and the size of solute should be equal to 1 Â (Angstrom).

8 0
3 years ago
Read 2 more answers
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