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Levart [38]
3 years ago
8

Mei is standing next to a statue in the park. If Mei is 5 feet tall, her shadow is 3 feet long, and the statues shadow is 10 1/2

feet long, how tall is the statue.
Mathematics
1 answer:
alisha [4.7K]3 years ago
5 0
The problem presented above is an example in which we can use the concept of ratio and proportion. The ratio between the heights of Mei and the statue should be the same to the ratio of their shadows. Letting x be the height of the statue. 
                                  5 ft/ x ft = 3 ft / 10.5 ft
The value of x from the equation above is 17.5 ft. 
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Hat is the 68th term of sequence -8.6,-7.2,-5.8,-4.4,
Umnica [9.8K]
First find the law
8.6-1.4n
so, 64th is 8.6-1.4x64
I think is -81
5 0
3 years ago
Mom has ⅘ quart of strawberries. She needs to fill ¼-quart jars. How many jars will she be able to fill?
Blababa [14]
She will be able to fill 3 jars because 4/5=16/20 and 1/4 = 5/20 so 5/20 x 3 = 15/20
5 0
3 years ago
Louisa drew a polygon with six sides of equal length. If the perimeter of Louisa's polygon is 95.4 centimeters, how long is each
Agata [3.3K]

Answer:

15.9 centimeters

Step-by-step explanation:

the information we have is:

Perimeter: P=95.4cm

Number of sides of the polygon: n=6

since each side has equal length, we can use the following equation to find the measure of one side of the polygon, the equation for perimeter:

P=nl

where n is the number of sides and l is the length of each side.

So we clear for l and we get:

l=\frac{P}{n}

and subtituting the known values:

l=\frac{95.4cm}{6}\\ l=15.9cm

each side is 15.6 centimeters long

3 0
3 years ago
The A&M Hobby Shop carries a line of radio-controlled model racing cars. Demand for the cars is assumed to be constant at a
Bond [772]

Answer:

Step-by-step explanation:

A) Demand per month= 40 cars

Annual Demand (D)= 12*40 = 480

Fixed Cost per order (K)= 15

Holding Cost= 20% of cost= 60 *0.2 = 12

a. Economic Order Quantity=

Q^{*}={\sqrt {{\frac {2DK}{h}}}}

= √(2*480*15)/12

=34.64 ~ 35

Total Cost =P*D+K(D/EOQ)+h(EOQ/2) P= Cost per unit

= 60*480+ 15(480/35) + 12(35/2)

= 28800+ 205.71+ 210

=$29215.71

B). Backorder Cost (b)= $45

Qbo= Q* × √( b+h/ h)

= 35*√(12+45/ 45)

= 35* 1.12

=39.28 ~ 39

Shortage (S)= Qbo * (K/K+b)

= 39* (15/15+45)

= 39* 0.25

= 9.75

Total Cost Minimum=( bS2/ 2Qbo) + P (Qbo- S)2/2Qbo + K(D/Qbo)

=45* 9.752 / 2* 392 + 60 (39-9.75)2/ 2* 392 + 15 ( 480/39)

= 1.40+ 21.9.+ 184.61

=$207.91

C)Length of backorder days (d) = Demand ÷ amount of working days

d = 480 ÷ 300

d = 1.6

Calculate the backorders as the maximum number of backorders divided by the demand per day

s/d = 9.75/1.6 = 6.09 days (answer)

D) Calculate the difference in total between not using backorder:

$207.85 + $207.85 - 207.91 = $207.79

The saving in using backorder is $207.79.

Therefore I would recommend using a backorder

6 0
3 years ago
Mr. Juarez opened a savings account with an initial deposit of $560 and will not make any additional deposits or withdrawals. Th
olga_2 [115]

Answer:

$576.80

Step-by-step explanation:

We have been given that Mr. Juárez opened a savings account with an initial deposit of $560 and will not make any additional deposits or withdrawals. The account earns 1% simple interest.

We are asked to find the total amount that Mr. Juárez will have in his account at the end of 3 years.

We will use simple interest formula to solve our given problem.

A=P (1+rt)

A = Final amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

Let us convert 1% into decimal form,

1%=1/100=0.01

P=$560 and t=3

A=$560 (1+0.01(3))

A=$560 (1+0.03)

A= $560 (1.03)

A= $576.80

Therefore, Mr. Juárez will have $576. 80 in his account at the end of 3 years. Hope this helps!

5 0
3 years ago
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