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Verizon [17]
4 years ago
6

The absolute value of a number is​

Mathematics
2 answers:
DENIUS [597]4 years ago
5 0

Answer:

The absolute value of a number is always positive. So that means you circled the correct one. GOOD JOB!!!!!!!!!!!!!!!!!!!!!!!

Step-by-step explanation:

Elanso [62]4 years ago
5 0

absolute value will always be positive

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100 points + Brainy<br><br> Math help please
aev [14]

Answer:

Q = -6

Step-by-step explanation:

To find the answer to this, you first must multiply the first function by 2:

2 x (x - 3y = 4)

2x - 6y = 8

Which then means that the second function is the same. This means that to find Q you need to find the number that changed +Qy into -6:

2x - 6y = 8

2x + Qy = 8

The 2x's cancel out, and then remove the equals and the 8:

-6y = Qy

<h3>So Q must be -6</h3>
<h2>Hope this helps!</h2>
5 0
4 years ago
Read 2 more answers
45%of the total population of a village are males and there are 22000 females Find the male population of the village.​
Greeley [361]

Answer:

18000

Step-by-step explanation:

The 22000 females make up 55% of the population. So, we divide 22000 by 0.55 to get the total population.

22000 ÷ 0.55 = 40000

Now we take our total population and subtract 22000 to get the number of males in the population.

40000 - 22000 = 18000

The male population of the village is 18000.

7 0
3 years ago
4/15q-7/3=5 solve for q what is the answer
MAVERICK [17]
The answer is 27 1/2.
5 0
3 years ago
Read 2 more answers
What is a simple way to solve for the sum and difference of 2 cubes? For example, 27+64<img src="https://tex.z-dn.net/?f=x%5E3"
salantis [7]

Answer:

(3 + 4x)(9 - 12x + 16x²) = 0

(4m - 1)(16m² + 4m + 1) = 0

Step-by-step explanation:

Here we have to solve the sum of two cubes which is 27 + 64x^{3}

Now, the equation is 27 + 64x^{3} = 0

⇒ 3³ + (4x)³ = 0

⇒ (3 + 4x)[3² - 3(4x) + (4x)²] = 0

⇒ (3 + 4x)(9 - 12x + 16x²) = 0

So, (3 + 4x) = 0 or (9 - 12x + 16x²) = 0

Therefore, from the above two relation we can solve for x.

One root will be - \frac{3}{4} and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.  

Again, we have to solve the difference of two cubes which is 64m^{3} - 1

Now, the equation is 64m^{3} - 1 = 0

⇒ (4m)³ - 1³ = 0

⇒ (4m - 1)[(4m)² + 4m(1) + 1²] = 0

⇒ (4m - 1)(16m² + 4m + 1) = 0

So, (4m - 1) = 0 or (16m² + 4m + 1) = 0

Therefore, from the above two relation we can solve for m.

One root will be \frac{1}{4} and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.  (Answer)

8 0
4 years ago
What is the domain of the function
IRINA_888 [86]
\sqrt{5+x} is defined as long as 5+x\ge0, or x\ge-5. However, \dfrac1x is undefined when x=0. This point is contained in the set \{x|x\ge-5\}, so we need to exclude it. We can write the domain in several ways.

\{x|x\ge-5~\land~x\neq0\}
-5\le x
[-5,0)\cup(0,\infty)
6 0
3 years ago
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