Answer:
(the statement does not appear to be true)
Step-by-step explanation:
I don't think the statement is true, but you CAN compute the intercepted arc from the angle.
Note that BFDG is a convex quadrilateral, so its angles sum to 360. Since we know the inscribed circle touches the angle tangentially, angles BFD and BGD are both right angles, with a measure of 90 degrees.
Therefore, adding the angles together, we have:
alpha + 90 + 90 + <FDG = 360
Therefore, <FDG, the inscribed angle, is 180-alpha (ie, supplementary to alpha)
Answer:
D. (2, 0)
Step-by-step explanation:
The solutions are the two points of intersection of the graphs:
(-2, -4) and (2, 0)
The latter of these corresponds to choice D, the one you have marked.
Answer:
hehc dhcbshhceucuiifvbrifrjvrjv
Step-by-step explanation: