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eimsori [14]
3 years ago
8

You're a 7th grade math teacher and you want to create an experiment for your class with red, yellow and purple marbles in the b

ag. You want the theoretical probability of getting red to be 1/2. The theoretical probability of drawing yellow be 1/3 and the theoretical probability of drawing purple being 1/6. If you want a total of 1260 marbles in the bag.
1. How many red marbles are you going to put in to the bag and why?
2.How many marblesare yout going to put into the bag and why?
3. How many purple marbles are you going to put into the bag and why?
Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
8 0

630 red marbles

420 yellow marbles

210 purple marbles

because 1260 x 1/2 = 630, 1260 x 1/3 = 420, 1260 x 1/6 = 210

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Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.
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Answer:

1) \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}} = 32

Step-by-step explanation:

1) \frac{(-2)^{-5}}{(-2)^{-10}}

Solving using exponent rule: a^{-m}=\frac{1}{a^m}

\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32

So, \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4}

Using the exponent rule: a^m.a^n=a^{m+n}

We have:

2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}

We also know that: a^{-m}=\frac{1}{a^m}

Using this rule:

2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}

So, 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2

Solving:

(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}

So, (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}}

We know that: a^{-m}=\frac{1}{a^m}

\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32

So, \frac{2}{2^{-4}} = 32

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Step-by-step explanation:

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Answer:

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Rate: 20 squids per 36 eels

Simplified ratio:

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Unit ratio:

20/36 squids per eel (dividing by 36)

Please mark Brainliest if this helps!

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