Answer:
In parametric form:
Step-by-step explanation:
We first find the mid point:
Then, a vector parallel to the z-axis is:
Then remember the equation of a line passing through point 
and parallel to the vector 
is:
So, in this problem we get:
After combining the two vectors:
In parametric form:
The points of the graph are> (1,1), (2,2), (3,4), (4,8).
Then the sequence is:
- for the x-coordinate: 1, 2, 3, 4, 5, 6, 7, ...
- for the y-coordinate: 1, 2, 4, 8, which is: 2^0, 2^1, 2^2, 2^ 3, ... so the next y-coordinates are 16, 32, 64, 128, ...
So, the sequence is: 1, 2, 4, ,8, 16, 32, .... 2^x.
Hello from MrBillDoesMath!
Answer:
a(n) = -3n , n>= 1
Discussion:
a(1) = -3
a(2) = -6
a(3) = -9
a(4) = -12
The pattern looks like a(n) = -3n
Thank you,
MrB
Do 11/24 + 2/5. then subtract your answer from 240
<span>9, 12, 19, 30, ...
</span>formula for the nth term is;
<span>2n^2 + 3n - 10</span>
