Find the nth term of this quadratic sequence 3, 11, 25, 45, .
1 answer:
The term of the given quadratic sequence is found to be 3n² - n + 1 using the principle of mathematical induction.
Given,
In the question:
The quadratic sequence is :
3, 11, 25, 45, ...
To find the nth term of the quadratic sequence.
Now, According to the question;
The first term of the sequence is 3, the second term is 11, the third term is 25, and the fourth term is 45.
The difference between the first and second terms can be calculated as follows:
11-3 = 8
The difference between the second and third terms can be calculated as follows:
25-11 = 14
The difference between the third and fourth terms can be calculated as follows:
45-25 = 20
The sequence is expressed as follows:
3,3+8,11+11,25+20,...
The difference between consecutive terms expands by 6.
Use the principle of mathematical induction.
6
= 3n(n+1)
The sequence's nth term can be calculated as follows:
term = 3n(n+1) - 4n + 1
= 3n² - n + 1
Hence, the term of the given quadratic sequence is found to be 3n² - n + 1 using the principle of mathematical induction.
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Answer:
Step-by-step explanation:
The record of the statistics and the summary statistics which are the missing files in the question are attached below.
From the given information:
The null hypothesis and the alternative hypothesis can be represented by :
There is no difference between the average time spend by men and women at gym each week
The average time spend by men is greater than the average time spend by women at the gym each week
From the summary statistics in the attached file below:
The p-value = 0.3253
Level of significance = 5% = 0.05
Therefore; it is obvious that the p-value is greater than the level of significance i.e (0.3253 > 0.05)
Hence; there is no enough evidence to reject the null hypothesis
CONCLUSION: We conclude that the mean number of minutes exercised per week is larger for men than women at the this gym.
Answer:
<h2>NONE OF THEM</h2>Step-by-step explanation:
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y and x intercepts are and approximately
respectively
for A, C and D :
x intercept the value of y=0, and y intercept x=0.
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x and y intercepts are and approximately
respectively
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they are not equal to the x and y intercepts of the given graph