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Mazyrski [523]
3 years ago
8

Please help me with this

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0
Im srry i cant help with that because K12 will not let me look up answers i bet
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Which of the following is a solution of x2 + 6x = −18? x = 3 − 3i x = −3 + 3i x = −6 + 3i x = 6 − 3i
Marina86 [1]

Step 1 ) Move all terms right side of the equation.

\displaystyle\ x^{2} + 6x = -18

\displaystyle\ x^{2} + 6x + 18 = -18 + 18

\displaystyle\ x^{2} +6x + 18 = 0

Step 2 ) Apply quadratic formula. (Note: There are 2 solutions)

\displaystyle\ x^{2} +6x + 18 = 0

\displaystyle\ x = \frac{-b\sqrt{b^{2}-4ac}}{2a}, \displaystyle\ x = \frac{-b-\sqrt{b^{2}-4ac}}{2a}

\displaystyle\ x = \frac{-6+\sqrt{6^{2}-4 * 18}}{2} , \displaystyle\ x = \frac{-6-\sqrt{6^{2}-4*18}}{2}

\displaystyle\ x = \frac{-6+6i}{2} ,

\displaystyle\ x = \frac{-6-6i}{2}

Step 3 ) Simplify.

\displaystyle\ x = \frac{-6+6i}{2} ,

\displaystyle\ x = \frac{-6-6i}{2}

\displaystyle\ x = -3+ 3i,

\displaystyle\ x = -3 - 3i

Since the options only provide one of the answer we found, the answer is...

\displaystyle\ x = -3 - 3i

•

•

- <em>Marlon Nunez</em>

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3 years ago
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Write an expression, using an exponent, that is equivalent <br> 9×9×9×9×9×9×9.
uranmaximum [27]
The answer would he 98
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3 years ago
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What is the square root of 49 multiplied by the square root of 9
fiasKO [112]
First we need to find the the answer to both the square root of 49 and 9.

The "square root" is a term referring to a number, multiplied by itself (x • x) would be = to your square root.

So for example: Square root of 16 = 4 because 4*4=16 

So lets get out numbers:

\sqrt{9} =3&#10;
\sqrt{49}=7

Now you multiply 3*7 (or 7*3) and you get 21.

Final answer: 21

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Express the repeating decimal 2.7 as a fraction.
sergeinik [125]
2/9 is the answer broski
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Write a description of this inequality: <br> -5a+3&gt;1
iren [92.7K]
The sum of -5a and 3 is greater than 1.

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