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Mazyrski [523]
3 years ago
8

Please help me with this

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0
Im srry i cant help with that because K12 will not let me look up answers i bet
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Help answering this simple Series Question? I don't know what I did wrong!
Tatiana [17]
Looks like you just evaluated the summand for the given value of n, whereas the question is asking you to find the value of the sum for the first n terms.

Let S_k=\displaystyle\sum_{n=1}^k\frac3{(-2)^n}. Then S_k is the kth partial sum.

S_1 happens to be the first term in the series, which is why that box is marked correct:

S_1=\displaystyle\sum_{n=1}^1\frac3{(-2)^n}=\frac3{(-2)^1}=-1.5

But the next partial sum is not correct:

S_2=\displaystyle\sum_{n=1}^2\frac3{(-2)^n}=\frac3{(-2)^1}+\frac3{(-2)^2}=-0.75

and this is not the same notion as the second term (which indeed is 0.75) in the series.
5 0
3 years ago
Write 0.8 repeating as a fraction
Alborosie
The answer is 8/9 i believe.
4 0
3 years ago
Read 2 more answers
Write the expression as one<br> involving only sin x and cos x.<br> sin 2x + cos x
AfilCa [17]

Answer:

sin 2x + cos x =  2 sin x cos x + cos x = (2 sin x + 1)cos x

Step-by-step explanation:

Given the expression: sin 2x + cos x,

then we can use the formula: sin 2x = 2 sin x cos x, which gives:

sin 2x + cos x =  2 sin x cos x + cos x = (2 sin x + 1)cos x

So there you have two expressions in terms of sin x and cos x, as requested. :D

6 0
2 years ago
What is 25 and -2 1/5
ICE Princess25 [194]

6/962...............................................

5 0
2 years ago
G
inessss [21]
I have no idea what this is asking honestly but i hope you figure it out
7 0
2 years ago
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