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Mazyrski [523]
3 years ago
8

Please help me with this

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0
Im srry i cant help with that because K12 will not let me look up answers i bet
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Simplified form of 4(12x+16)
Ierofanga [76]

Answer:

The given expression simplified is <em>48x + 64.</em>

Step-by-step explanation:

Solving this problem entails of simplifying the expression provided. We'll use the distributive law, or the distributive property, to write the expression in the simplest form.

Distributive law states:

  • a(b + c) ⟶ (a × b) + (a × c)

We know that...

  • a = 4
  • b = 12x
  • c = 16

Following the rules of distributive law, we can set up the expression to match this property.

a(b + c)  ⟶  4(12x + 16)  ⟶  (4 × 12x) + (4 × 16)

The expression will now be easier to simplify. Here, the last step would be to multiply the terms within the parentheses. Remember that we <u>cannot</u> multiply a number by a variable. When you multiply '4' by '12x', just multiply twelve and four, and leave the variable as is.

(4 × 12x) + (4 × 16)

48x + (4 × 16)

48x + 64

Think back on what I mentioned earlier about not being able to multiply a number by a variable. The same rule applies to adding two terms, in which one is a constant and the other consists of a coefficient <u>and variable</u>. Our simplified expression has '48x', which is a coefficient and variable, and '64', which is a constant. This means we cannot add these two terms together.

Our expression seems to be in the simplest form because no further actions can be taken. The correct answer should be <em>48x + 64.</em>

6 0
3 years ago
The mean score of 8 players is 14.5. If the highest individual score is removed the mean of the score of the remaining 7 players
AfilCa [17]

Answer:

The highest score is 32.

Step-by-step explanation:

We are given the following in the question:

The mean score of 8 players is 14.5.

Let x denote the highest score.

If x is removed, the mean of the score of the remaining 7 players is 12.

Formula for mean:

\bar{x} = \dfrac{\displaystyle\sum x_i}{n}

Putting values, we get:

14.5 = \dfrac{\displaystyle\sum x_i}{8}\\\\\Rightarrow \displaystyle\sum x_i = 116\\\\12 = \dfrac{\displaystyle\sum y_i}{7}\\\\\Rightarrow \displaystyle\sum y_i  = 84\\\\\displaystyle\sum y_i = \displaystyle\sum x_i -x \\\\84 = 116 - x\\\Rightarrow x = 32

Thus, the highest score is 32.

4 0
4 years ago
Please Help me it’s geometry
mote1985 [20]

Answer:

Option C.

Step-by-step explanation:

Given: In \Delta OPQ,m\angle O=107^{\circ},m\angle P=28^{\circ}.

In \Delta OPQ,

m\angle O+m\angle P+m\angle Q=180^{\circ}    (Angle sum property)

107^{\circ}+28^{\circ}+m\angle Q=180^{\circ}

135^{\circ}+m\angle Q=180^{\circ}

m\angle Q=180^{\circ}-135^{\circ}

m\angle Q=45^{\circ}

Now,

m\angle O>m\angle Q>m\angle P

In a triangle, the greatest angle has largest opposite side and smallest angle has smallest opposite side. So, we conclude that

PQ>OP>QO

Therefore, the correct option is C.

7 0
4 years ago
How do I simplify 6 - x + (x - 1)
levacccp [35]

Answer:

<h2>5</h2>

Step-by-step explanation:

6-x+(x-1)=6-x+x-1\\\\\text{combine like terms}\\\\=(-x+x)+(6-1)\\\\=5

5 0
3 years ago
F(x)= x^2-8x+15
mash [69]
If I'm reading your equations correctly, they are:f(x)=x2-8x+15g(x)=x-3h(x)=f(x)/g(x)The domain of a function is the set of all possible inputs, what we can plug in for our variable.The largest two limitations on domains (other than explicit limitations, like in piecewise functions) are radicals and rational functions. With radical expressions we know that we CANNOT take an even root of a negative number. I don't see that problem here. With rationals we know that we CANNOT divide by zero. So the question becomes, when does h(x) ask us to divide by zero? When is the denominator of h(x) zero?Since the denominator of h(x) is g(x), we cannot let g(x) equal zero. So when does that happen? when x-3=0 or when x=3. I hope you see here that if x=3, then g(x)=0, and so h(x)=f(x)/0, which we CANNOT do. The domain of h(x) is all real numbers not equal to 3. There is more going on here. If you had factored f(x) first, you could have written h(x) in a confusing way:h(x)=( f(x) ) / ( g(x) )h(x)= ( (x-5)(x-3) ) / (x-3) Right here, it looks like (x-3) will cancel out from the top and bottom of your fraction. It does, in a way. The graph of h(x) will behave exactly like the line y=x-5, except that it has a hole in it at x=3 (check this! it's cool!)SOOO, the takeaway is that it is better to determine limitations on your domain BEFORE over-simplifying your equations.
6 0
3 years ago
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