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Kruka [31]
3 years ago
11

Draw the Lewis structure for methane (CH4) and ethane (C2H6) in the box below. Then predict which would have the higher boiling

point. Finally, explain how you came to that conclusion.

Chemistry
1 answer:
Alinara [238K]3 years ago
7 0

Answer:

Ethane would have a higher boiling point.

Explanation:

In this case, for the lewis structures, we have to keep in mind that all atoms must have <u>8 electrons</u> (except hydrogen). Additionally, each carbon would have <u>4 valence electrons</u>, with this in mind, for methane we have to put the hydrogens around the carbon, and with this structure, we will have 8 electrons for the carbon. In ethane, we will have a bond between the carbons, therefore we have to put three hydrogens around each carbon to obtain 8 electrons for each carbon.

Now, the main difference between methane and ethane is an <u>additional carbon</u>. In ethane, we have an additional carbon, therefore due to this additional carbon, we will have <u>more area of interaction</u> for ethane. If we have more area of interaction we have to give <u>more energy</u> to the molecule to convert from liquid to gas, so, the ethane will have a higher boiling point.

I hope it helps!

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Why are the noble gases (group 18) inert?
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“Conductor, circuit breaker, switch” use the words provided to write the function of fuses. 
bezimeni [28]

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Compounds put together will form -
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4 0
3 years ago
The bonds of oxygen molecules are broken by sunlight. The minimum energy required to break the oxygen-oxygen bond is 495 kJ/mol
olga_2 [115]

Answer:

The wavelength of sunlight is required to break the bond in one oxygen molecule is 242 nm.

Explanation:

Energy required to break the 1 mol oxygen-oxygen bond:

=495 kJ=495000J

1 mol = 6.022\times 10^{23} molecules

Energy required to break 1 molecule of oxygen molecule= E

= E=\frac{495000 J}{6.022\times 10^{23}}=8.219\times 10^{-19} J

The energy required to break the  1 molecule of oxygen is equal to enrgy of one photon of a sunlight.

E=\frac{h\times c}{\lambda}

where,

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E = energy of the photon

h = Planck's constant = 6.63\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda=\frac{h\times c}{E}

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The wavelength of sunlight is required to break the bond in one oxygen molecule is 242 nm.

4 0
3 years ago
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