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Daniel [21]
4 years ago
11

A buffer is 0.282 m c6h5cooh(aq and 0.282 m na(c6h5coo(aq. calculate the ph after the addition of 0.150 moles of nitric acid to

1.0 l of the buffer. the pka of c6h5cooh is 4.20.
Chemistry
1 answer:
Sindrei [870]4 years ago
7 0
You have to use the Henderson-Hasselbalch equation. Keep in mind that because the Pka is given the equation changes form slightly:

PH = Pka + log[acid/base]

Step 1 (Figure out the concentrations):

0.282 M of Acid (C6H5OOH) - 0.150 M = 0.132 M of acid
0.282 M of Base (C6HCOO) + 0.150 M = 0.432 M of bas3

Step 2 (Plug into equation):

PH = Pka + log[acid/base]
PH = 4.20 + log[0.132 M/0.432 M]

PH = 3.69

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What is the highest energy to which doubly ionized helium atoms (alpha particles) can be accelerated in a DC accelerator with 3
pentagon [3]

Answer:

Highest energy will be equal to 9.6\times 10^{-13}J

Explanation:

Charged on doubly ionized helium atom q=2e=2\times 1.6\times 10^{-19}C=3.2\times 10^{-19}C

It is accelerated with maximum voltage of 3 MV

So voltage V=3\times 10^6volt

Now energy is given by E=qV=3.2\times 10^{-19}\times 3\times 10^6=9.6\times 10^{-13}J

So highest energy will be equal to 9.6\times 10^{-13}J

5 0
3 years ago
Question 15 (1 point)
Digiron [165]

Answer:

Atoms are electrically neutral because the number of protons, which carry a 1+ charge, in the nucleus of an atom is equal to the number of electrons, which carry a 1- charge, in the atom. The result is that the total positive charge of the protons cancels out the total negative charge of the electrons so that the net charge of the atom is zero. Most atoms, however, can either gain or lose electrons; when they do so, the number of electrons becomes different from the number of protons in the nucleus. The resulting charged species is called an ion.

Cations and anions

When a neutral atom loses one or more electrons, the total number of electrons decreases while the number of protons in the nucleus remains the same. The result is that the atom becomes a cation—an ion with a net positive charge.

The opposite process can also occur. When a neutral atom gains one or more electrons, the number of electrons increases while the number of protons in the nucleus remains the same. The result is that the atom becomes an anion—an ion with a net negative charge. We can illustrate this by examining some very simple cations and anions, those formed when a single hydrogen atom loses or gains an electron.

Note: Hydrogen is actually somewhat unusual in that it readily forms both cations and anions. Most elements much prefer to form only one or the other. In terms of its electron configuration, can you explain why hydrogen can form both cations and anions? Feel free to post in the comments at the end of the article!

A hydrogen cation, a hydrogen atom, and a hydrogen anion.

A hydrogen cation, a hydrogen atom, and a hydrogen anion.

Classification cation neutral atom anion

No. of protons 111 111 111

No. of electrons 000 111 222

Net charge 111++plus 000 111-−minus

If a neutral hydrogen atom ( \text{H}Hstart text, H, end text, center) loses an electron, it becomes a hydrogen cation ( \text{H}^+H  

+

start text, H, end text, start superscript, plus, end superscript, left). Conversely, if the neutral \text{H}Hstart text, H, end text atom gains an electron, it becomes a hydrogen anion ( \text{H}^-H  

−

start text, H, end text, start superscript, minus, end superscript, right), also known as a hydride ion. Image credit: adapted from Boundless Learning, CC BY-SA 4.0.

In the center column, we have a diagram of a single, neutral hydrogen atom. It contains one proton and one electron; thus, its net charge is zero. If hydrogen loses its electron, it forms the cation \text{H}^+H  

+

start text, H, end text, start superscript, plus, end superscript (left column). The \text{H}^+H  

+

start text, H, end text, start superscript, plus, end superscript cation has a net charge of 1+ from the one proton in the nucleus since there are no electrons to cancel out the positive charge. If neutral hydrogen gains an electron, it forms the anion \text{H}^-H  

−

start text, H, end text, start superscript, minus, end superscript (right column). The \text{H}^-H  

−

start text, H, end text, start superscript, minus, end superscript anion has a net charge of 1- because it has one extra electron compared to the total number of protons.

Explanation: Hopes this gives a better explanation on them!

6 0
3 years ago
Classify each of the following particulate level illustrations as a representation of either a pure substance, a homogeneous mix
Anarel [89]

Answer:

The classification and illustrations are attached in the drawing.

Explanation:

It is possible to identify the pure substance observing the figure, since it is the only one that has 2 joined atoms (purple and blue) which forms a single compound.

On the other hand, the homogeneous mixture is identified by noting that its atoms are more united with respect to the heterogeneous mixture, highlighting that in homogenous mixtures the atoms, elements or substances are not visible to the naked eye and are in a single phase, instead in the heterogeneous mixture if they can be differentiated.

4 0
3 years ago
How many moles of oxygen atoms are in 7.9E-1 moles of CO_2
Ilya [14]

Answer:

The number of moles of O atom in (7.9\times10^{-1}) mol of CO_{2} = 1.6

Explanation:

1 molecule of CO_{2} contains 2 atoms of O

So, (6.023\times 10^{23}) molecules of  CO_{2} contains (2\times6.023\times10^{23}) atoms of O.

We know that 1 mol of an atom/molecule/ion represents 6.023\times10^{23} numbers of atoms/molecules/ions respectively.

So, (6.023\times 10^{23}) molecules of  CO_{2} is equal to 1 mol of CO_{2}.

(2\times6.023\times10^{23}) atoms of O is equal to 2 moles of O atom.

Hence, 1 mol of CO_{2} contains 2 moles of O atom.

Therefore, (7.9\times10^{-1}) mol of CO_{2} contains (2\times7.9\times10^{-1}) moles of O atom or 1.6 moles of O atom.

3 0
3 years ago
El agua del mar contiene aproximadamente un 3,0 % m/v de sal (NaCl, 58,44 g/mol), (asuma que es la única fuente de cloruros) si
Alchen [17]

Answer:

s = 4.41 g/L.

Explanation:

¡Hola!

En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:

PbCl_2(s)\rightleftharpoons 2Cl^-(aq)+Pb^{2+}(aq)

Lo cual hace que la expresión de equilibrio se calcule como:

Ksp=[Pb^{2+}][Cl^-]^2

Y que en términos de la solubilidad molar, s, se resuelve como:

1.6x10^{-5}=s(2s)^2\\\\1.6x10^{-5}=4s^3\\\\s=\sqrt[3]{\frac{1.6x10^{-5}}{4} } \\\\s=0.0159molPbCl_2/L

Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):

s=0.0159molPbCl_2/L*\frac{278.1gmolPbCl_2}{1molmolPbCl_2} \\\\s=4.41g/L

¡Saludos!

7 0
3 years ago
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