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wariber [46]
3 years ago
6

In the free radical chlorination of methylcyclopentane, what is the total number of distinct monochlorinated compounds, includin

g stereoisomers, that would be formed?
A) 4
B) 6
C) 8
D) 10
Chemistry
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer:

B) 6

Explanation:

Methylcyclopentane consist of 3 types of hydrogen which are 1° (primary), 2° (secondary) and 3° (tertiary) hydrogen atoms. In the chlorination of methylcyclopentane, there are four monochlorinated products possible and two stereoisomers.

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Refer to the attachment for answer.

SOME EXTRA INFORMATION:

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BartSMP [9]

The complete balanced chemical equation for this is:

<span>3KOH  +  H3PO4  -->  K3PO4  +  3H2O</span>

 

First we calculate the number of moles of H3PO4:

moles H3PO4 = 0.650 moles / L * 0.024 L = 0.0156 mol

 

From stoichiometry, 3 moles of KOH is required for every mole of H3PO4, therefore:

moles KOH = 0.0156 mol H3PO4 * (3 moles KOH / 1 mole H3PO4) = 0.0468 mol

 

Calculating for volume given molarity of 0.350 M KOH:

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7 0
3 years ago
Which of the following groups have seven valence electrons and are very reactive?
valina [46]

Answer:

Column 17 halogens

Explanation:

To answer the question we need to know the following;

What are valence electrons?

  • Valence electrons are outermost electrons in the outermost energy level of an atom of any element.

What are halogens?

  • Halogens are group 7 elements that have seven valence electrons. They include, chlorine, fluorine, iodine, etc

What is the reactivity of halogens?

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Explanation:

1 mol = 22.4 l

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7 0
3 years ago
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