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jarptica [38.1K]
3 years ago
12

Which statement is true regarding a titration? It measures the amount of heat given off in combustion reactions. It determines h

ow much water to add in a dilution. It determines the concentration of an unknown substance in neutralization reactions. It determines if a reaction will take place in single replacement reactions. It is used to make a solution of designated molarity.
Chemistry
2 answers:
exis [7]3 years ago
3 0
C) It determines the concentration of an unknown substance in neutralization reactions.
pishuonlain [190]3 years ago
3 0

Answer:  It determines the concentration of an unknown substance in neutralization reactions.

Explanation: Titration is defined as the process where a solution of known concentration is used to determine the concentration of an unknown solution.

Volumetric titrations are usually used for neutralization reactions.

When an acid and base reacts to give salt and water, the reaction is called as  neutralization reaction.

The normality equation used during the titration is:

N_1V_1=V_2V_2

N_1= Normality of acid solution

V_1= volume of acid solution

N_2= Normality of basic solution

V_2= Volume of basic solution

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Electrcity cannot pass through a/an
evablogger [386]
Electricity can't pass through an insulator.

Hope this helps!
4 0
4 years ago
20 points to anybody that can answer all 3 of these questions
Brilliant_brown [7]

Answer:

1. 2AgO2 --> 4 Ag + O2

2. Decomposition

3. 2NaBr + CaF2 --> 2NaF + CaBr2

Explanation:

3 0
3 years ago
Read 2 more answers
If the pH is 10, what is the concentration of hydroxide ion?
AleksandrR [38]

Answer : The correct option is, 10^{-4}M

Explanation : Given,

pH = 10

First we have to calculate the pOH.

pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-10=4

Now we have to calculate the OH^- concentration.

pOH=-\log [OH^-]

4=-\log [OH^-]

[OH^-]=1.0\times 10^{-4}M

Therefore, the OH^- concentration is, 1.0\times 10^{-4}M

7 0
3 years ago
An unknown triprotic acid (H3A) is titrated with NaOH. After the titration Ka1 is determined to be 0.0053 and Ka2 is determined
Savatey [412]

Answer:

Ka3 for the triprotic acid is 7.69*10^-11

Explanation:

Step 1: Data given

Ka1 = 0.0053

Ka2 = 1.5 * 10^-7

pH at the second equivalence point = 8.469

Step 2: Calculate Ka3

pKa = -log (Ka2) = 6.824

The pH at the second equivalence point (8.469) will be the average of pKa2  and pKa3. So,

8.469 = (6.824 + pKa3) / 2

pKa3 = 10.114

Ka3 = 10^-10.114 = 7.69*10^-11

Ka3 for the triprotic acid is 7.69*10^-11

6 0
4 years ago
Which of the following atoms is likely to transfer (and lose) an electron when it forms an ion? Please choose the correct answer
mestny [16]

Answer:

An atom containing 11 electrons

Explanation:

Metal atoms form ions by a loss of electrons whereas non-metal atoms form ions by the gain of electrons.

The group 1 elements or alkali metals form lose their one valence shell electrons when forming ions; Group 2 metals lose two while Group 3 lose three. On the other hand, non-metal atoms found in Group 5, 6, and 7 forms ions by gaining one, two and three electrons respectively.

Using the electronic configuration of atoms, their groups in the Periodic Table can be determined.

An atom containing 6 electrons has the configuration 2,4 and thus belongs to Group 4.

An atom with 2 electrons belongs to Group 2

An atom with 11 electrons has the configuration 2,8,1 and thus belongs to Group 1

An atom with 10 electrons has the configuration 2,8 and thus belongs to Group 8

An atom with 8 electrons has the configuration 2,6 and thus belongs to Group 6.

From the above, it can be seen that an atom containing 11 electrons belongs to Group 1 and will lose an electron to form an ion.

8 0
3 years ago
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