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jarptica [38.1K]
3 years ago
12

Which statement is true regarding a titration? It measures the amount of heat given off in combustion reactions. It determines h

ow much water to add in a dilution. It determines the concentration of an unknown substance in neutralization reactions. It determines if a reaction will take place in single replacement reactions. It is used to make a solution of designated molarity.
Chemistry
2 answers:
exis [7]3 years ago
3 0
C) It determines the concentration of an unknown substance in neutralization reactions.
pishuonlain [190]3 years ago
3 0

Answer:  It determines the concentration of an unknown substance in neutralization reactions.

Explanation: Titration is defined as the process where a solution of known concentration is used to determine the concentration of an unknown solution.

Volumetric titrations are usually used for neutralization reactions.

When an acid and base reacts to give salt and water, the reaction is called as  neutralization reaction.

The normality equation used during the titration is:

N_1V_1=V_2V_2

N_1= Normality of acid solution

V_1= volume of acid solution

N_2= Normality of basic solution

V_2= Volume of basic solution

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A civil engineering student is considering buying an electric car. However, the conscious student wants to make sure her carbon
svetlana [45]

Answer:

\text{An gasoline-powered vehicle has }\\\boxed{\text{five times the carbon footprint}}\text{ of an electric vehicle.}

Explanation:

1. Miles travelled in an average month  

\text{Miles} = \text{1 mo} \times \dfrac{\text{52 wk}}{\text{12 mo}} \times \dfrac{\text{5 da}}{\text{1 wk}} \times \dfrac{\text{16 mi}}{\text{1 da}} = \text{347 mi}

2. Using a gasoline powered vehicle  

(a) Moles of heptane used  

n = \text{347 mi} \times \dfrac{\text{1 gal}}{\text{36.5 mi}}\times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{679.5 g}}{\text{1L}} \times \dfrac{ \text{1 mol}}{\text{100.20 g}}= \text{244 mol}

(b) Equation for combustion  

C₇H₁₆ + O₂ ⟶ 7CO₂ + 8H₂O  

(c) Moles of CO₂ formed  

n = \text{244 mol heptane} \times \dfrac{\text{7 mol CO$_{2}$}}{\text{1 mol heptane}} = \text{1710 mol CO$_{2}$}

(d) Volume of CO₂ formed  

At 20 °C and 1 atm, the molar volume of a gas is 24.0 L.  

V = \text{1710 mol } \times \dfrac{\text{24.0 L}}{\text{1 mol}} \times \dfrac{\text{1 gal}}{\text{3.785 L}} = \textbf{10 800 gal}

3. Using an electric vehicle  

(a) Theoretical energy used  

\text{Theor. Energy} = \text{347 mi} \times \dfrac{\text{1 kWh}}{\text{5.2 mi}} = \text{66.7 kWh theor.}

(b) Actual energy used  

The power station is only 85 % efficient.  

\text{Actual energy used} = \text{66.7 kWh theor.} \times \dfrac{\text{100 kWh actual}}{\text{ 85 kWh theor.}}\times \dfrac{\text{3600 kJ}}{\text{1 kWh}}\\\\ = 2.82\times 10^{5} \text{ kJ}\

(c) Combustion of CH₄

CH₄ + 2O₂ ⟶ CO₂ +2 H₂O

(d) Equivalent volume of CO₂

The heat of combustion of methane is -802.3 kJ·mol⁻¹  

V= 2.82\times 10^{5}\text{ kJ} \times \dfrac{\text{1 mol methane}}{\text{802.3 kJ}} \times \dfrac{\text{1 mol CO$_{2}$} }{\text{1 mol methane}} \times \dfrac{ \text{24.0 L}}{ \text{1 mol CO$_{2}$}}\\\\ \times \dfrac{\text{1 gal}}{\text{3.875 L}} = \textbf{2180 gal}

4. Comparison  

\dfrac{V_{\text{gasoline}}}{V_{\text{electric}}} = \dfrac{10800}{2180} = 5.0\\\\ \text{An gasoline-powered vehicle has }\\ \boxed{\textbf{ five times the carbon footprint}}\text{ of an electric vehicle.}

6 0
3 years ago
Calculate the gravitational force of attraction between a 26kg boy and his 5.1kg dog when they are separated by 0.19m
Pavel [41]

Answer:

Gravitational force of attraction G(f) = 2.44 x 10⁻⁷ (approx.)

Explanation:

Given:

Mass M1 = 26 kg

Mass M2 = 5.1 kg

Distance r = 0.19 m

Find:

Gravitational force of attraction G(f)

Computation:

Gravitational force of attraction G(f) = G(m1)(m2)/r²

Gravitational force of attraction G(f) = [6.67 x 10⁻¹¹](26)(5.1)/(0.19)²

Gravitational force of attraction G(f) = 8.84 x 10⁻⁹ / 0.0361

Gravitational force of attraction G(f) = 2.44 x 10⁻⁷ (approx.)

6 0
3 years ago
Phenols do not exhibit the same pka values as other alcohols; they are generally more acidic. Using the knowledge that hydrogen
nevsk [136]

Answer:

Phenols do not exhibit the same pka values as other alcohols;

They are generally more acidic.

Using the knowledge that hydrogen acidity is directly related to the stability of the anion formed, explain why phenol is more acidic than cyclohexane.

Explanation:

According to Bromsted=Lowry acid-base theory,

an acid is a substance that can release H^{+} ions when dissolved in water.

So, acid is a proton donor.

If the conjugate base of an acid is more stable then, that acid is a strong acid.

In the case of phenol,

the phenoxide ion formed is stabilized by resonance.

C_6H_5OH -> C_6H_5O^- +H^+

The resonance in phenoxide ion is shown below:

Whereas in the case of cyclohexanol resonance is not possible.

So, cyclohexanol is a weak acid compared to phenol.

7 0
3 years ago
How will freezing the juice affect its mass?
expeople1 [14]

Answer:

Mass increases since its going from liquid to solid.

Explanation:

8 0
3 years ago
Which is a characteristics of all ions
Sholpan [36]

Answer:

All ions must a overall charge

Explanation:

4 0
3 years ago
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