Question

A

Answer 1

Answer:

$9.8ms^{-2}$

Explanation:

using the equation :

$acceleration = \frac{final velocity - initial velocity}{timetaken} \\ a =\frac{v-u}{t}$

where v is 98m/s

u is 0m/s

t is 10seconds

$a=\frac{98m/s- 0m/s}{10} \\a=\frac{98}{10}\\ a=9.8m/s^{2}$