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vesna_86 [32]
3 years ago
13

What is the slope intercept form for (0,2) and (1,-2)

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
8 0

Answer:

The slope intercept is 2 because in the equation

y = mx + b

and if I were to fill in the equation the the rise over run would be 1/2 and b would be 2.

y = 1/2 +2

timama [110]3 years ago
5 0

Answer:

Step-by-step explanation:

y =mx+b

y=-4x+2

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3 years ago
Evaluate: 23 + x/8 for x = 8
sveta [45]
23 + x/8

substitute 8 in x

23 + 8/8

23 + 1 = 24
8 0
3 years ago
Read 2 more answers
1.
Taya2010 [7]

Answer:

-7x+7y=-49 matches this graph.

maddymcg408 avatar

The correct option is (B)

Step-by-step explanation: We are given to match the graph with its correct equation.

From the graph, we note that

there is a straight line where the points (7, 0) and (0, -7) lie on it.

So, the slope of the line is given by

Since the line passes through the point (7, 0), so its equation will be

Thus, the required equation of the graphed line is

Option (B) is CORRECT.

Step-by-step explanation:

-7x+7y=-49 matches this graph.

maddymcg408 avatar

The correct option is (B)

Step-by-step explanation: We are given to match the graph with its correct equation.

From the graph, we note that

there is a straight line where the points (7, 0) and (0, -7) lie on it.

So, the slope of the line is given by

Since the line passes through the point (7, 0), so its equation will be

Thus, the required equation of the graphed line is

Option (B) is CORRECT.

maddymcg408 avatar

jr3974 avatar

jr3974

10/31/2017

Mathematics

College

answered

Match the graph with its equation.

7x + 7y = 0

7x – 7y = –49

7x + 7y = 49

–7x +7y = –49

2

SEE ANSWERS

maddymcg408 avatar

^_^

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3 years ago
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3 years ago
An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
8090 [49]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by  

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

t= \frac{-80\pm \sqrt{6400+19200}}{-32}

t= \frac{-80\pm \sqrt{25600}}{-32}  

Simplify:

t = -\frac{5}{2} = -2.5 sec and t = \frac{15}{2} = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec


6 0
3 years ago
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