3 years ago

Consider the function f(x)=8-3x^2 find the value of f(x) when x=3

Mathematics

1 answer:

Eva8 [605]3 years ago

4 0

To solve f(x) functions in this case you simply put 3 wherever x is in your problem. f(3)=8-3(3)^2 this equals -19

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lukranit [14]

So, initially 240 $\frac{3}{8}$ -212 $\frac{12}{3}$ were empty:

this is :

$240 \frac{3}{8} - 212 \frac{12}{3} = 240 \frac{3}{8} - 212 +4 = 240 \frac{3}{8} - 216= 24 \frac{3}{8}$

12/4 is 4 so that's why i substituted it with 4.

now, later 27 1/3 were used so we add this tho the original empty space

$24 \frac{3}{8}+ 27 \frac{1}{3}$ = $24 \frac{9}{24}+ 27 \frac{8}{24}$ = $51 \frac{17}{24}$

which is the result!

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3 years ago

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Zinaida [17]

Answer:

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Step-by-step explanation:

You add the -7 and -1 and then put the x in front of your answer.

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3 years ago

Read 2 more answers

Help ASAP geometry !