Which unit would you most likely use to measure the length of a train

Given: △ABC, m∠C=90° m∠ABC=30°, AL ∠ bisector CL=6 ft. Find: LB

vlada-n [284]

For a better understanding of the solution given here please go through the diagram in the file attached.

To solve this question we will make use of the "Triangle Angle Bisector Theorem", which states that, "An angle bisector of an angle of a triangle divides the opposite side in two segments that are proportional to the other two sides of the triangle."

Thus, in our question, we will have:

$\frac{LB}{CL}= \frac{AB}{AC}$

The above equation can be rearranged as:

$LB=CL\times \frac{AB}{AC}=\frac{CL}{(\frac{AC}{AB})}$ ...(Equation 1)

If we have a proper look at the denominator which is $\frac{AC}{AB}$ , we note that in $\Delta ABC$ , $\frac{AC}{AB}=Sin(\angle ABC)=Sin(30^\circ)$

Thus, (Equation 1) wil give us:

$LB=\frac{CL}{Sin(30^\circ)} =\frac{6}{0.5}=12$

<u>Therefore, LB= 12 feet</u>

3 0

3 years ago

Recall that a right triangle is a triangle with one right angle. One angle of a triangle measures 89.99°. Can the triangle be a

Anastasy [175]

Yes because the right triangle has a right angle which will equal to 90° you can place 89.99 to the nearest whole number which will give you a right angle.

7 0

3 years ago

Can u guys PLEASE ANSWER THIS QUESTION ASAP URGENTLY

makvit [3.9K]

Answer:

x^2-4x+3

Step-by-step explanation:

Since the zeroes of the quadratic are 1 and 3, we can set up an equation in factored form:

(x-1)(x-3)

=x^2-4x+3

We can further check that this is the right answer by evaluating it at the vertex:

(2)^2-4*2+3=-1

Since that corresponds to the graph, the answer is x^2-4x+3

3 0

3 years ago

Alfie is going fishing and takes a flask of tea. His flask holds approximately 5 cups of tea. Estimate how much his flask holds

cricket20 [7]

forty five ounces per. flask

6 0

3 years ago

In a sample of eight whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a sta

Advocard [28]

Answer:

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.3246

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.3646\frac{0.06}{\sqrt{8}} = 0.0502$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg

The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

8 0

3 years ago