1.94
Divide 7.76 by 4 to get the cost of each glue stick
Answer:
0.0918
Step-by-step explanation:
We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The mean and standard deviation of average spending of sample size 25 are
μxbar=μ=95.25
σxbar=σ/√n=27.32/√25=27.32/5=5.464.
So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The z-score associated with average spending $102.5
Z=[Xbar-μxbar]/σxbar
Z=[102.5-95.25]/5.464
Z=7.25/5.464
Z=1.3269=1.33
We have to find P(Xbar>102.5).
P(Xbar>102.5)=P(Z>1.33)
P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)
P(Xbar>102.5)=0.5-0.4082
P(Xbar>102.5)=0.0918.
Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.
<h2><u><em>
1/3 < 5/6 < 3/2</em></u></h2><h2><u><em>
</em></u></h2><h2>This Would Be The Order From Least To Greatest</h2>
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Answer:
no
Step-by-step explanation:
Answer:
A 24 because half of 12 is 6 then 6 x 4 is 24
B 90÷3 is 30 which is 2/3 of 45
Hope this helps you
