Answer:
Step-by-step explanation:
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We are told that Emerson struck out 112 times in 350 at-bats. We are asked to find the percent of strike outs per at-bat.
Let us find out 112 is what percent of 350.
Therefore, Emerson struck out 32% of the at-bats.
The first thing we are going to do is draw a diagram of the situation to help us to solve the situation.
We an draw tow similar triangle between the length of the shadows and the height of the stick and the pole.
Since <span>meter stick has a length of 1 meter, the height of our smaller triangle is 1 meter. Let </span>
be height of of the pole. Since both triangles are similiar we can establish a proportion between their corresponding sides and solve for :
We can conclude that the pole is 4.04 meters tall.
We an draw tow similar triangle between the length of the shadows and the height of the stick and the pole.
Since <span>meter stick has a length of 1 meter, the height of our smaller triangle is 1 meter. Let </span>
We can conclude that the pole is 4.04 meters tall.
The sum of the given series can be found by simplification of the number
of terms in the series.
- A is approximately <u>2020.022</u>
Reasons:
The given sequence is presented as follows;
A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021
Therefore;
The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;
Therefore, for the last term we have;
2 × 2043231 = n² + 3·n + 2
Which gives;
n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0
Which gives, the number of terms, n = 2020
Which gives;
- A ≈ <u>2020.022</u>
Learn more about the sum of a series here: