James Callahan has available a 10% alcohol solution and a 60% alcohol solution. Find how many liters of each solution he should
mix to make 50 liters of a 40% alcohol solution?
1 answer:
Let
x-------------> liters of <span>10% alcohol solution
</span>y-------------> liters of 60% alcohol solution
we know that
x+y=50----------------------> x=50-y-----------------> equation 1
0.10x+0.60y=0.40*50----------> 0.10x+0.60y=20---------> equation 2
substitute 1 in 2
0.10*(50-y)+0.60y=20---------> 5-0.10y+0.60y=20
5+0.50y=20------------> 0.50y=15-----------------> y=30
x+y=50----------> x=50-30---------> x=20
the answer is
20 liters of 10% alcohol solution
30 liters of 60% alcohol solution
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