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zhannawk [14.2K]
4 years ago
7

PLEASE HELP!!!!!!!!!!!!!!!!

Mathematics
1 answer:
umka21 [38]4 years ago
3 0
Im kid and im 8 i cat answer that


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PLS HELP ME WITH THIS QUESTION
andreyandreev [35.5K]

Answer:

-0.88

Step-by-step explanation:

(w^2/x - 3)÷ 10.z

(-6/1.2 - 3)÷ 10. -6/7

(-5-3)÷ 9.14

(-8)÷ 9.14

-8/9.14

= -0.88

3 0
3 years ago
How do you divide 100.5/1.5
Artist 52 [7]
 <span>It is: 1.5/100.5 = 1/67      </span>4 goes into 9 two times with a remainder of 1. Bring down the 6 and 4 goes into 16 4 times.So 96 divided by 4 is 24

7 0
3 years ago
Read 2 more answers
________________hundredths = 0.80
bulgar [2K]
The answer is eighty.
6 0
3 years ago
Could someone explain this to me?
Ilya [14]
This is a simple differentiation problem. Let's start by taking the derivative of both sides (with respect to x):
5y^4\frac{dy}{dx}+6y^2x+6x^2y\frac{dy}{dx}+20x^3 = 0

Simplify:
\frac{dy}{dx} (5y^4+6x^2y) + 6y^2x+20x^3 = 0

Solve for dy/dx:
\frac{dy}{dx} = \frac{-6y^2x-20x^3}{5y^4+6x^2y}

Now, plug in the given points:
\frac{dy}{dx} = \frac{-6(2)^2(-1)-20(-1)^3}{5(2)^4+6(-1)^2(2)} = \frac{24+20}{80+12}

Further simplification gives:
\frac{dy}{dx}|_{(2,-1)} =\frac{44}{92} =  \frac{11}{23}

So, your answer is 11/23 or B.
7 0
4 years ago
An earth satellite remains in orbit at a distance of 11550 km from the center of the earth. what speed would it have to maintain
marishachu [46]
<span>11,550 km has to be changed to 11,550,000 meters

G · m · t² = 4 · π² · r³  we can change that to
</span>t² = (4 · π² · r³) / <span>(G · m )
t^2 = 4*PI^2*r^3 / (G*m)
</span>t^2 = 4*PI^2*<span>(11,550,000)^3 / 6.67*10^-11*5.98*10^24kg
t^2 = </span> <span> <span> <span> 6.083*10^22 </span> </span> </span> <span><span> </span> </span> / <span> <span> <span> 3.9</span></span></span>9 * 10^14
t^2 =  <span> <span> <span> 152,500,000</span></span></span>
t = <span>12,350 seconds
</span>and its orbital distance it travels is 11,550 * 2*PI = 70,050 kilometers

Therefore, it is traveling at 70,050 km / 12,350 second which equals
5.67 km per second which  <em>is 5,670 meters per second.</em>


Source:
http://www.1728.org/kepler3a.htm



4 0
4 years ago
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