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Gekata [30.6K]
2 years ago
9

In which direction must the graph of Rx) = 7% be shifted to produce the graph of g(x) = 7% + 7?

Mathematics
1 answer:
joja [24]2 years ago
5 0

Answer:

B. Up

Step-by-step explanation:

If you alter a function by adding or subtracting a constant to the end of the expression, then the graph will slide up (down if subtracting) If you alter the x value by altering the expression in close to the x with addition or subtraction the graph will slide left or right.

Vertical translations (sliding up or down) go up when adding and down when subtracting as you would expect it to.

Horizontal translations are the oppoof what you might expect. A (x-h) will shift the graph right, while a (x+k) will shift the graph left.

The answer to your question is UP.

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Answer:

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Step-by-step explanation:

6 0
2 years ago
Solve the inequality 2x>30+5/4x
insens350 [35]

Answer:

Step-by-step explanation:

2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} }  \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0

x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }

case~2

if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0

8 0
1 year ago
Find the particular solution to y'=2sin(x) given the general solution is y=C-2cos(x) and the initial condition y(pi/3)=1
mezya [45]

ANSWER

The particular solution is:

y=2-2 \cos(x)

EXPLANATION

The given Ordinary Differential Equation is

y'=2 \sin(x)

The general solution to this Differential equation is:

y=C-2 \cos(x)

To find the particular solution, we need to apply the initial conditions (ICs)

y( \frac{\pi}{3} ) = 1

This implies that;

C-2 \cos( \frac{\pi}{3} ) = 1

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4 0
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Answer:

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Volume formula for cylinder: V = πr²×h

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Volume = π × 5.5² × 16

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3 0
3 years ago
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ra1l [238]

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-45x + 18x²    Your answer is A ( the first option)

3 0
3 years ago
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