Answer:
A. 2H₂O₂ → 2H₂O + O₂
Explanation:
- 2. H₂O₂ + OI⁻ → H₂O + O₂ + I⁻
If we <u>make a net sum of both reactions</u>, we're left with:
- H₂O₂ + I⁻ + H₂O₂ + OI⁻ → H₂O + OI⁻ + H₂O + O₂ + I⁻
Grouping species:
- 2H₂O₂ + OI⁻ + I⁻ → 2H₂O + OI⁻ + O₂ + I⁻
There is OI⁻ at both sides, so it is eliminated -same goes for the catalyst, I⁻-.
Thus the answer is option A.
Answer:
(a) from the anode to the cathode through the external circuit
Explanation:
In an electrochemical cell, there are two half cells; the oxidation half cell and reduction half cell. Oxidation typically refers to loss of electrons and reduction refers to gain of electrons.
Electrons always flow from the anode to the cathode or from the oxidation half cell to the reduction half cell.
The electrical circuit in an electrochemical cell confirms the flow of electron. Usually a light bulb is attached. The correct option is;
(a) from the anode to the cathode through the external circuit
Answer:
Phosphorus atoms can bond with oxygen atoms to form ester groups. These can bond with carbon atoms, yielding a large number of organic phosphorus chemicals. These are found in many important biological processes
Nitrogen, Oxygen, and Fluorine do not follow this trend. The noble gas electron configuration will be close to zero because they will not easily gain electrons.
Answer:
I'm not sure if this right because i've only taken one year of Chemistry but the answer I got was
A. 24 g
