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katen-ka-za [31]
3 years ago
10

How so I figure out the number of elecrons per energy level?THIS IS MY OWN CREATED ELEMENT!!

Chemistry
2 answers:
Korolek [52]3 years ago
7 0

You would divide 140 (How many electrons) by the numbers of lines.

Helga [31]3 years ago
6 0

divide the number of electrons by the number of lines


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What is the mass of 5 moles of Fe2(CO3)3 ?
sineoko [7]

Answer:

1218.585

Explanation:

Looking at the subscripts we know there are 2 atoms of Fe, 3 atoms of C, and 6 of O.

Take the molar mass of each atom (from the periodic table) and multiply by the # of atoms

Fe: 55.845×2= 111.69

C: 12.011×3= 36.033

O:15.999×6=95.994

Add the values together: 243.717 g/mol

That is 1 mole of the molecule. Multiply by 5 for the final answer.

243.717×5=1218.585

7 0
2 years ago
Lewis structure for carbon tetrabromide (CBrÁ), in which a central carbon atom is bound to four atoms of the group 7A element br
nlexa [21]
Remember that carbon has 4 electrons in its valence shell meanwhile bromine has 7

So i think the lewis structure would be :

Br

C       Br      Br  

Br

Hope this helps

7 0
3 years ago
1. Who is the father of atomic theory? 2. Who discovered the electron? 3. Who expressed particles by wave equations? 4. Who rese
krek1111 [17]
1. Who is the father of atomic theory?
Dalton

2. Who discovered the electron?
<span>Thomson
</span>
3. Who expressed particles by wave equations?
<span>Schrödinger
</span>
4. Who researched on radioactivity?
Curie

<span>5. Who discovered the "open spaces" model?
</span><span>Rutherford
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6. Who applied quantum theory to atoms? 
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6 0
3 years ago
Read 2 more answers
Which statement correctly describes a chemical reaction?
Trava [24]
The correct answer is C
6 0
3 years ago
How many sulfur atoms are present in 25.6 g of Al2(S2O3)3
IgorC [24]

Given the mass of Al_{2}(S_{2}O_{3})_{3}=25.6 g

The molar mass of Al_{2}(S_{2}O_{3})_{3}=390.35g/mol

Converting mass of Al_{2}(S_{2}O_{3})_{3}to moles:

25.6 g Al_{2}(S_{2}O_{3})_{3}*\frac{1molAl_{2}(S_{2}O_{3}}{390.35 gAl_{2}(S_{2}O_{3}} =0.0656molAl_{2}(S_{2}O_{3}

Converting mol Al_{2}(S_{2}O_{3})_{3}to mol S:

0.0656mol Al_{2}(S_{2}O_{3})_{3}*\frac{6molS}{1mol Al_{2}(S_{2}O_{3})_{3}}=0.3936 molS

Converting mol S to atoms of S using Avogadro's number:

1 mol = 6.022*10^{23}atoms

0.3936mol S *\frac{6.022*10^{23}atoms S}{1 mol S}=2.37*10^{23} S atoms

5 0
2 years ago
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