<u>Answer:</u> The pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.
<u>Explanation:</u>
There are three types of solution: acidic, basic and neutral
To determine the type of solution, we look at the pH values.
- The pH range of acidic solution is 0 to 6.9
- The pH range of basic solution is 7.1 to 14
- The pH of neutral solution is 7.
We are given:
Concentration of HI = 0.100 M
1 mole of HI produces 1 mole of hydrogen ions and 1 mole of iodide ions
To calculate the pH of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
![[H^+]=0.100M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.100M)
Putting values in above equation, we get:
To calculate the pOH of the solution, we use the equation:
pH + pOH = 14
Hence, the pH and pOH of the solution is 1 and 13 respectively and the solution is acidic in nature.
One
Let's start by stating what we know is wrong. Equilibrium is achieved when the reactants and products have a stable concentration. That makes D incorrect. Equilibrium is not established until about the 6th or 7th second.
The fact that you get any products at all means that the reactants will become products. Just who is favored has to be looked at very carefully. The products start very near 0. They go up until their concentration at equilibrium. When the reach equilibrium, the products have increased to 17. The reactants have dropped from 40 to 27. By a narrow margin, I would say the products are favored.
C is incorrect. There are still reactants left.
E is incorrect. the reactants started out with a concentration of 40. The reaction is not instantaneous. The concentration was highest at 40 or right at the beginning. This assumes that the reactants were mixed and the products were produced and the water/liquid amount has not changed.
B is incorrect. The concentration of the reactants is higher at equilibrium.
A is wrong. It is product favored.
I'm getting none of the above.
Problem Two
AgBr is insoluble (very). You'd have to work very hard to get them to separate into their elemental form. Just putting AgBr in water isn't enough. Lots of heat and lots of electricity are needed to get the elemental form.
I suppose you should pick B. Mass must be preserved. But if you balanced the equation, it would work with heat and electricity.
Ionic bonds are forces that hold together electrostatic forces of attractions between oppositely charged ions. Ionic bonds have an electronegativity difference greater than or equal to 2. Covalent bonds have an electronegativity difference that is less than 2.
Answer:
Are basic:
[OH⁻] = 3.13x10⁻⁷M and [H₃O⁺] = 9.55x10⁻⁹M
Explanation:
A solution is basic when pH = - log [H₃O⁺] is higher than 7.
It is possible to convert [OH⁻] to [H₃O⁺] using:
[H₃O⁺] = 1x10⁻¹⁴ / [OH⁻]
a. [OH⁻] = 3.13x10⁻⁷M
[H₃O⁺] = 1x10⁻¹⁴ / [3.13x10⁻⁷M]
[H₃O⁺] = 3.19x10⁻⁸M
pH = - log [H₃O⁺] = 7.50
[OH⁻] = 3.13x10⁻⁷M is basic
b. pH = -log [H₃O⁺] = - log 0.000747M = 3.13.
This solution is not basic
c. [H₃O⁺] = 9.55x10⁻⁹M
pH = 8.02
This solution is also basic.
