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julia-pushkina [17]
3 years ago
5

Stirring will A. Increase a reaction B. Decrease a reaction C. Cause no change D. Create a catalyst

Chemistry
1 answer:
lbvjy [14]3 years ago
8 0
A. Increase reaction
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]Which of the following describes the arrangement of particles in plasma?The particles are ionized and move independently of eac
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The arrangement of the particles in a plasma would be that the particles are ionized and move independently of each other. Plasma is also called an ionized gas where it has free charged particles and are moving regardless of each other.
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3 years ago
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What r variable's :) :) :) :) :)
zhannawk [14.2K]

Answer: an element, feature, or factor that is liable to vary or change.

"there are too many variables involved to make any meaningful predictions"

Explanation:

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3 years ago
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What mass of NaC6H5COO should be added to 1.5 L of 0.40 M C6H5COOH solution at 25 °C to produce a solution with a pH of 3.87 giv
statuscvo [17]

Answer:

41 g

Explanation:

We have a buffer formed by a weak acid (C₆H₅COOH) and its conjugate base (C₆H₅COO⁻ coming from NaC₆H₅COO). We can find the concentration of C₆H₅COO⁻ (and therefore of NaC₆H₅COO) using the Henderson-Hasselbach equation.

pH = pKa + log [C₆H₅COO⁻]/[C₆H₅COOH]

pH - pKa = log [C₆H₅COO⁻] - log [C₆H₅COOH]

log [C₆H₅COO⁻] = pH - pKa + log [C₆H₅COOH]

log [C₆H₅COO⁻] = 3.87 - (-log 6.5 × 10⁻⁵) + log 0.40

[C₆H₅COO⁻] = [NaC₆H₅COO] = 0.19 M

We can find the mass of NaC₆H₅COO using the following expression.

M = mass NaC₆H₅COO / molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = M × molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = 0.19 mol/L × 144.1032 g/mol × 1.5 L

mass NaC₆H₅COO = 41 g

7 0
3 years ago
For every action there is an equal and opposite reaction is known as? *
wolverine [178]

Answer:

Newton's third law

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3 years ago
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How many moles of water are in 1.23x10^18 water molecules
Harlamova29_29 [7]

By 1.23 x 1024 you mean 10 to the power of 24 molecules? If so all you need to do is divide the number of molecules you have by Avagadros number, 6.022 x 10^23. This will give you the mols of water, or the mols of anything, since there is always 6.022 x 10^23 molecules in 1 mol of substance.


1.23x10^24 atoms/6.022x10^23 atom/mol = 2.04 mol H20


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3 years ago
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