The graph on #6 describes a scatterplot. Because years of experience is the input, this makes the starting salary our output. Finding the best fitting line in a scatterplot requires the line to follow a trajectory similar to that of the points. As a result, there will be outliers. Since I don't know what "the calculator" is meant by this problem, I have used a different program. I hope it works for you. Good luck.
3.15. Just find the unit rate which is 1.5 and multiply that by 3
Answer:
4
Step-by-step explanation:
If Judge is x years old and Eden is 6 years older, then Eden is x + 6 years old.
The second part tells us that Eden will be twice as old as Judge in two years.
This means that in two years: (Eden's age) = 2 * (Judge's age).
Since we know that Eden's age can be represented as x + 6 and Judge's age can be represented as x, we can write this: x + 6 = 2 * x
Simplify the equation:
x + 6 = 2x
6 = x = Judge's age (in two years)
If Judge is 6 two years later, then he must be 4 now.
To check our work, we can just look at the problem. Judge is 4 years old and Eden is 6 years older than Judge (that means Eden is 10 right now). Two years later, Eden is 12 and Judge is 6, so Eden is twice as old as Judge. The answer is correct.
Answer:
x = 3.464
Step-by-step explanation:
7x^2 - 84 = 0
7x^2 = 84
x^2 = 12
x= 3.464
Given that:
Consider it is 
instead of 10 on two places.
is between 3 and 4. So, Beau thinks a good estimate for is = 3.5.
Solution:
To find , Beau found 3² = 9 and 4² = 16.
He said that since 10 is between 9 and 16.
Since 10 is close to 9, therefore must be close to 3. So, Beau's estimate is high.
Now,
Since, 10 lies between 9.61 and 10.24, therefore must be lies between 3.1 and 3.2.
Therefore, the estimated value of is 3.15.
