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mrs_skeptik [129]
3 years ago
12

A cannon ball is shot straight upward with a velocity of 72.50 m/s. How high is the cannon ball above the ground 3.30 seconds af

ter it is fired? (Neglect air resistance.)
Physics
1 answer:
disa [49]3 years ago
6 0

Answer:

Explanation:

Given

Cannon is fired with a velocity of u=72.50\ m/s

Using Equation of motion

y=ut+\frac{1}{2}at^2

where

y=displacement

u=initial\ velocity

a=acceleration

t=time

after time t=3.3 s

y=72.50\times 3.3-\frac{1}{2}\times 9.8\times (3.3)^2

y=239.25-53.36

y=185.89\ m

So after 3.3 s cannon ball is at a height of 185.89 m

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