Increasing the focal lenght
Answer:
3
Explanation:
v = v⁰ (its original speed) + a (negative acceleration) X t² (time)
v = 15 - 10 x 1.2 = 15 - 12 = 3 (it's slowing down)
Answer:
0.24 kg used up
Explanation:
He has a mass of 67 kg
The gravitational constant is 9.81 m/s^2
The distance upward is 3500 m
W = m*g*h
W = 67 * 9.81 * 3500
Work = 2,300,445 Joules
Work = 2300 kj
work = 2.30 * 10^6 joules in scientific notation.
Part B
He needs 4 times this amount to climb the mountain because the body is only 25% efficient in converting energy.
4*2.30 * 10^6 = 9.20 * 10^6 Joules of energy are therefore required.
The total amount in a kg of fat = 3.8 * 10^7 joules
x kg of fat is needed to provide 9.20.*10^6 joules
1 kg / (3.8 * 10^7 J ) = x kg / (9.20 * 10^6 J)
9.20 * 10 ^6 * 1 = 3.8 * 10^7 *x
9.20 * 10 ^6 / 3.8 * 10^7 = x
x = 0.24 kg of fat are needed
Answer:
Low satellite has high orbital velocity
Explanation:
let v be the orbital speed of the satellite orbiting at a height h is given by

where, M be the mass of planet, r be the radius of planet and h be the height of planet from the surface of planet.
here we observe that more be the height lesser be the orbital velocity.
So, a satellite which is at low height has high orbital velocity.