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3 years ago

S Problem Set 2.) 6.4 x 109 nm to cm

Physics

1 answer:

anyanavicka [17]3 years ago

8 0

Answer:

$6.4\cdot 10^2 cm$

Explanation:

First of all, let's convert from nanometres to metres, keeping in mind that

$1 nm = 10^{-9} m$

So we have:

$6.4\cdot 10^9 nm \cdot 10^{-9} m/nm = 6.4 m$

Now we can convert from metres to centimetres, keeping in mind that

$1 m = 10^2 cm$

So, we find:

$6.4 m \cdot 10^2 cm/m = 6.4\cdot 10^2 cm$

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An igneous rock becomes buried, is subject to high heat and pressure, and recrystallizes. This rock then is eroded, transported,

nevsk [136]

Answer:

Answered

Explanation:

When an igneous rock becomes buried, is subjected to high heat and pressure, and recrystallizes it is formed into Metamorphic rock. Now this rock is eroded, transported, deposited and subsequently lithified to be converted into Sedimentary rock.

The same igneous rock is first converted into Metamorphic and then into sedimentary by the process of weathering.

5 0

3 years ago

Vector A has y-component Ay= +15.0 m . A makes an angle of 32.0 counterclockwise from the +y-axis. What is the x component of A?

Gemiola [76]

Answer:

x-component=-9.3 m

Magnitude of A=17.7m

Explanation:

We are given that

$A_y=+15 m$

$\theta=32^{\circ}$

We have to find the x-component of A and magnitude of A.

According to question

$A_y=\mid A\mid cos\theta$

Substitute the values then we get

$15=\mid A\mid cos32$

$\mid A\mid =\frac{15}{cos32}=\frac{15}{0.848}$

$\mid A\mid=17.7$ m

$tan\theta=\frac{perpendicular\;side}{Base}$

$tan32=\frac{A_x}{A_y}=\frac{A_x}{15}$

$0.62\times 15=A_x$

$A_x=9.3$

The value of x-component of A is negative because the vector A lie in second quadrant.

Hence, the x- component of A=-9.3 m

6 0

2 years ago

Read 2 more answers

Suppose the magnitude of the proton charge differs from the magnitude of the electron charge by a mere 1 part in 109

Oksana_A [137]

Answer:

A) F = 1.09 10 5 N, b) Yes

Explanation:

Part A

For this exercise we need the number of free electrons in copper, as the valence of copper +1 there is a free electron for each atom. Let's use the concept of density to find the mass of copper in the sphere

ρ = m / V

.m = ρ V = ρ 4/3 π r³

The radius is half the diameter

r = 1.9 10⁻² / 2 = 0.95 10⁻² m

ρ = 8960 kg / m3

m = 8960 4/3 π (0.95 10⁻²)³

m = 3.2179 10⁻² kg

The molecular weight of copper is 63,546 g / mol which has 6,022 10²³ atoms

With this we can use a rule of proportions to enter the number of atom is this mass

#_atom = 6.022 10²³ 3.2179 10⁻² / 63.546 10⁻³

#_atom = 3,049 10²³

Therefore there is the same number of electrons, as they indicate that the charge of the protone and the electon differs by 1/10⁹ the total charge for each spherical is

q = e / 10⁹ #_atom

q = e / 10⁹ 3,049 1023

q = 3,049 10⁴ (-1.6 10⁻¹⁹)

q = -4,878 10-5 C

Electric force is

F = k q₁q₂ / r²

F = k q² / r²

Let's calculate

F = 8.99 10⁹ (4.878 10⁻⁵)²2 / (1.4 10⁻²)²

F = 1.09 10 5 N

This is a force of repulsion.

Part B

The magnitude of this force is in very easy to detect

4 0

3 years ago

Whats the force of a pitching machine on a baseball

ira [324]

Answer:

kinetic

Explanation:

8 0

2 years ago

Read 2 more answers

a cell phone uses 3.0V battery. the circuit board needs a 0.05 A current. what size resistor is needed to generate this current

san4es73 [151]

Answer:

60 Ohms

Explanation:

Ohms law states that the voltage in the circuit is directly proportional to the current through the circuit components and expressed as

V=IR

Where V is the voltage, I is current and R is resistance

Making R the subject of the formula then

$R=\frac {V}{I}$

Substituting 3.0V for V and 0.05 A for I then

$R=\frac {3}{0.05}=60.0$

Therefore, resistance is 60.0 Ohms

7 0

3 years ago