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dmitriy555 [2]
3 years ago
14

TU has endpoints at T(5, -1) and U(1,-5). How long is TU?*

Mathematics
1 answer:
Fudgin [204]3 years ago
7 0

Answer:

\sqrt{32}

Step-by-step explanation:

We can first input our numbers into the distance formula to get:

\sqrt{(5-1)^2+(-1+5)^2}

Next we can solve within each parenthesis:

\sqrt{(4)^2+(4)^2}

Next we  can solve the squares. The square of 4 is 16 so we can input that into the equation

\sqrt{16+16}

Now we can add the 2 numbers together:

\sqrt{32}

And that is our final number as \sqrt{32} is not a perfect square.

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