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Zepler [3.9K]
2 years ago
14

Write an equation of the line that is parallel to y = -x + 1

Mathematics
1 answer:
lorasvet [3.4K]2 years ago
8 0

Answer:

y+-x+1

Step-by-step explanation:

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What the answer fast
Dominik [7]

To solve this problem, first let x=0.933333(repeating). Then, you want to multiply both sides by 10 to get 10x = 9.33333 (repeating). Next, take equation 2 and minus equation 1 from it giving you 9x = 8.4. Finally, multiply both sides by 10 and you will get 90x = 84. Divide both sides by 90 giving x=84/90. Answer is 84/90. 84/90 can reduce to 14/15.

3 0
3 years ago
3-5n+4n=4. help please​
goblinko [34]

Answer:

n = -1

Step-by-step explanation:

3-5n+4n=4

3 - n = 4

-n = 1

n = -1

6 0
3 years ago
What numtber should the fraction 15/3 be mutiplied by in order to equal 1?
anzhelika [568]

Answer:1/5

Step-by-step explanation:

The fraction 15/3 equals 5.

15 ÷ 3 = 5

So, what number when multiplied by 5 equals 1?

1/5

Step-by-step explanation:

3 0
2 years ago
Ive been struggling with this problem can someone help. Thank you
borishaifa [10]

Answer:

70 degrees

Step-by-step explanation:

Angles 130 degrees and TUV are supplementary angles.  Thus, the latter is (180 - 120), or 60, degrees.  Now the sum of all three interior angles of this triangle must be 180 degrees:  (60 + 50 + >TUV) = 180, so >TUV is 70 degrees (answer C).

3 0
2 years ago
The rectangle shown has length AC = 32, width
Elena-2011 [213]

Answer:

A. 320

Step-by-step explanation:

See attachment for the figure

in order to determine Area of quadrilateral ABDF, we'll use the formula i.e

Area of quadrilateral ABDF = Area of AECD - Area of ΔBCD - Area of ΔDEF ->eq(1)

whereas, area of AECD = (AC × AE)

Area of ΔBCD = 1/2 (BC x CD)

Area of ΔDEF =1/2 ( EF x ED)

Substituting in eq(1)

eq(1)=>

Area of quadrilateral ABDF =  (AC × AE)  - 1/2 (BC x CD)- 1/2 ( EF x ED)

                  =(32 x 20) - 1/2(16 x 20) - 1/2(10 x 32)

                  = 640 - 160 - 160

                  = 640 - 320

                 = 320 square unit

Therefore, the area of quadrilateral ABDF is 320 square unit

8 0
3 years ago
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