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strojnjashka [21]
3 years ago
13

PLEASE I NEED HELP!!!

Mathematics
1 answer:
Volgvan3 years ago
4 0

A. The perimeter of quadrilaterals are same when x=2.

B. The area of quadrilaterals are same when x=4.6

<u>Step-by-step explanation</u>:

A. <u>Perimeter of the quadrilaterals must be equal.</u>

  • Perimeter of square is 4a.
  • where, a = 6
  • Perimeter of rectangle is 2(l+b).
  • where, l = 2 and b = (3x+4)

Perimeter of square = Perimeter of rectangle

4(6) = 2(2+3x+4)

⇒ 24 = 2(3x+6)

⇒ 24 = 6x + 12

⇒ 6x = 12

⇒ x = 12/6

x = 2

For x=2, the perimeters of both the quadrilaterals are same.

B. <u>Area of the quadrilaterals must be equal.</u>

  • Area of square is a².
  • where, a = 6.
  • Area of rectangle is l\timesb.
  • where, l = 2 and b = (3x+4)

Area of square = Area of rectangle

(6)² = 2(3x+4)

36 = 6x+8

6x = 28

x = 28/6

x = 4.6

For x=4.6, the area of both the quadrilaterals are same.

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Answer:

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Step-by-step explanation:

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CaHeK987 [17]

Answer:

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Step-by-step explanation:

a) -9( 4x - 6y - 10) = -36x + 54y + 90 not equal

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Use substitution. What is the solution to the system of equations? Use the drop-down menus to explain your answer.
Hoochie [10]

Answer:

The system of equations has one solution. The two equations are intersecting lines.

Step-by-step explanation:

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next, you have to distribute

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3 years ago
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