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3 years ago

What percent of 68 is 5?

1 answer:

3 0

X/y * 100 = percent
5 / 68 = 0.0735294117647059 

5/68 * 100= 7.35294117647059%

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Solve the equation.-21=m/3m m=7 m=-7 m=-63 m=63

Jlenok [28]

-21

I hope this helps and have a wonderful day filled with joy!!

<3

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3 years ago

Suppose you have a pocketful of change. You have some pennies (p) and some quarters (q). One expression could be used to describ

faltersainse [42]

Answer:

1.57

Step-by-step explanation:

So we have two equations regarding the number of quarters q and the number of pennies p:

$p+q$

Which represents the total amount of coins and

$0.01p+0.25q$

Which represents the total amount of money in dollars.

So we are asked to evaluation each expression for the situation in which we have 6 quarters and 7 pennies. Thus, plug 6 in for q and 7 in for p:

$p+q\\(7)+(6)=13$

This tells us that we have 16 coins in total.

$0.01(7)+0.25(6)\\=0.07+1.50\\=1.57$

This tells us that we have a total amount of $1.57.

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3 years ago

Read 2 more answers

Which is the place value of the 1 in the number 184,735?

malfutka [58]

The place value of 1 is hundred thousands.

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3 years ago

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What is the distance between the points (-4,0) and (-7, -14) ?

vlada-n [284]

Answer:

Step-by-step explanation:

(-4,0) ; (-7, -14)

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\ =\sqrt{(-7-[-4])^{2}+(-14-0)^{2}}\\\\ =\sqrt{(-7+4)^{2}+(-14)^{2}}\\\\=\sqrt{(-3)^{2}+(-14)^{2}}\\\\=\sqrt{9+196} \\\\=\sqrt{205} \\\\=14.3178$

7 0

3 years ago

Find expressions for the partial derivatives of the following functions:

nlexa [21]

Answer:

Step-by-step explanation: partial derivative is the differentiation of one variable e.g. X while leaving the values of the other variable e.g. Y

These four questions A, B, C and D have different functions separated by commas. I will not assume the commas to be something else like a plus sign.

A. f(x) = g'(x).k(y) , g'(x) + h(y)

f(y) = k'(y).g(x) , g(x) + h'(y)

B. f(x) = g'x (x+y)

f(y) = g'y (x+y) , h'y (y+z)

f(z) = h'z (y+z)

C. f(x) = f'x (xy) , f'x (zx)

f(y) = f'y (xy) , f'y (yz)

f(z) = f'z (yz) , f'z (zx)

D. f(x) = f'x (x) , g'(x) , h'x (x,y)

f(y) = h'x (x,y)

These are the partial derivative expressions for each variable in each function. You will need to pay a lot of attention to understand:

* while differentiating X alone, functions in Y which are separated by commas from the functions in X, are ignored totally because they are different questions

* In functions where X added to Y is in a bracket e.g. (x+y), to find the derivative of X, Y isn't thrown away because they are joined (by a plus sign) the derivative of X alone in this case would be f'x (x+y)

* f(x), just like g(x), simply means/represents a function in X hence f'(x) means the differentiation of all X-terms in that function

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3 years ago