Solve the equation.-21=m/3m<br> m=7<br> m=-7<br> m=-63<br> m=63

Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordl

Karo-lina-s [1.5K]

Full Question

Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordless, and the other six are corded phones. Suppose that these components are randomly allocated the numbers 1, 2, . . . , 18 to establish the order in which they will be serviced.

What is the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced?

What is the probability that two phones of each type are among the first six serviced?

Answer:

a. 0.149

b. 0.182

Step-by-step explanation:

Given

Number of telephone= 18

Number of cellular= 6

Number of cordless = 6

Number of corded = 6

a.

There are 18C6 ways of choosing 6 phones

18C6 = 18564

From the Question, there are 3 types of telephone (cordless, Corded and cellular)

There are 3C2 ways of choosing 2 out of 3 types of television

3C2 = 3

There are 12C6 ways of choosing last 6 phones from just 2 types (2 types = 6 + 6 = 12)

12C6 = 924

There are 2 * 6C6 * 6C0 ways of choosing none from any of these two types of phones

2 * 6C6 * 6C0 = 2 * 1 * 1 = 2.

So, the probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced is

3 * (924 - 2) / 18564

= 3 * 922/18564

= 2766/18564

= 0.149

b)

There are 6C2 * 6C2 * 6C2 ways of choosing 2 cellular, 2 cordless, 2 corded phones

= (6C2)³

= 3375

So, the probability that two phones of each type are among the first six serviced is

= 3375/18564

= 0.182

5 0

2 years ago

I really need help. Please answer as many as you can. I'm still figuring some out. Thanks!

Aliun [14]

Hey there, Simmonsalivia!

It seems that you are in a hurry so I will make it quick without explanation.
1) $\frac{17}{4}$ or $4 \frac{1}{4}$
2) $\frac{20}{3}$ or $6 \frac{2}{3}$
3) 11
4) $\frac{56}{15}$ or $3 \frac{11}{15}$
5) $\frac{9}{8}$ or $1 \frac{1}{8}$
6) $\frac{35}{18}$ or $1 \frac{17}{18}$
7) 4
8) $\frac{49}{12}$ or $4 \frac{1}{12}$
9) $\frac{55}{6}$ or $9 \frac{1}{6}$
10) 23 $\frac{3}{4}$ tablespoons of ground coffee.
11) She used $10 \frac{3}{8}$ amount of flour in total.
12) $\frac{16}{5}$ or $3 \frac{1}{5}$
13) 4
14) $\frac{47}{15}$ or $3 \frac{2}{15}$
15) $\frac{28}{3}$ or $9 \frac{1}{3}$
16) $\frac{68}{9}$ or $7 \frac{5}{9}$
17) $\frac{50}{9}$ or $5 \frac{5}{9}$
18) $\frac{11}{3}$ or $3 \frac{2}{3}$
19) $\frac{14}{5}$ or $2 \frac{4}{5}$
20) $\frac{16}{5}$ or $3 \frac{1}{5}$
21) Ty needed 7 paving stones.
22) Besides the top block, they needed 25 blocks to build the tower.

Thank you for using Brainly.
See you soon!

3 0

3 years ago

Julian calculates the volume of a rectangular prism with the dimensions 3/4ft by 4 feet by 1/2 ft. His work is shown here.

lbvjy [14]

Answer:

He multiplied the denominators incorrectly

Step-by-step explanation:

we know that

The volume of a rectangular prism is given by the formula

V=LWH

we have

L=3/4 ft

W=5/1 ft

H=1/2

substitute

V=(3/4)(5/1)(1/2)= 3x5x1= 15

₋₋₋₋₋₋₋₋ ₋₋₋₋ ft³

4x1x2= 8

therefore

He multiplied the denominators incorrectly

7 0

2 years ago

Match each equation with a solution from the list of values.

vova2212 [387]

Answer:

1. a=2.3

2. b=2.6

3. c=2.3

4.d=2.6

5. e=40

6. f=1/6

7. g=85

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which two tables represent the same function?

topjm [15]

Answer:

The 1st and the 5th tables represent the same function

Step-by-step explanation:

* Lets explain how to solve the problem

- There are five tables of functions, two of them are equal

- To find the two equal function lets find their equations

- The form of the equation of a line whose endpoints are (x1 , y1) and

(x2 , y2) is $\frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

* Lets make the equation of each table

# (x1 , y1) = (4 , 8) and (x2 , y2) = (6 , 7)

∵ x1 = 4 , x2 = 6 and y1 = 8 , y2 = 7

∴ $\frac{y-8}{x-4}=\frac{7-8}{6-4}$

∴ $\frac{y-8}{x-4}=\frac{-1}{2}$

- By using cross multiplication

∴ 2(y - 8) = -1(x - 4) ⇒ simplify

∴ 2y - 16 = -x + 4 ⇒ add x and 16 for two sides

∴ x + 2y = 20 ⇒ (1)

# (x1 , y1) = (4 , 5) and (x2 , y2) = (6 , 4)

∵ x1 = 4 , x2 = 6 and y1 = 5 , y2 = 4

∴ $\frac{y-5}{x-4}=\frac{4-5}{6-4}$

∴ $\frac{y-5}{x-4}=\frac{-1}{2}$

- By using cross multiplication

∴ 2(y - 5) = -1(x - 4) ⇒ simplify

∴ 2y - 10 = -x + 4 ⇒ add x and 10 for two sides

∴ x + 2y = 14 ⇒ (2)

# (x1 , y1) = (2 , 8) and (x2 , y2) = (8 , 5)

∵ x1 = 2 , x2 = 8 and y1 = 8 , y2 = 5

∴ $\frac{y-8}{x-2}=\frac{5-8}{8-2}$

∴ $\frac{y-8}{x-2}=\frac{-3}{6}=====\frac{y-8}{x-2}=\frac{-1}{2}$

- By using cross multiplication

∴ 2(y - 8) = -1(x - 2) ⇒ simplify

∴ 2y - 16 = -x + 2 ⇒ add x and 16 for two sides

∴ x + 2y = 18 ⇒ (3)

# (x1 , y1) = (2 , 10) and (x2 , y2) = (6 , 14)

∵ x1 = 2 , x2 = 6 and y1 = 10 , y2 = 14

∴ $\frac{y-10}{x-2}=\frac{14-10}{6-2}$

∴ $\frac{y-10}{x-2}=\frac{4}{4}======\frac{y-10}{x-2}=1$

- By using cross multiplication

∴ (y - 10) = (x - 2)

∴ y - 10 = x - 2 ⇒ add 2 and subtract y in the two sides

∴ -8 = x - y ⇒ switch the two sides

∴ x - y = -8 ⇒ (4)

# (x1 , y1) = (2 , 9) and (x2 , y2) = (8 , 6)

∵ x1 = 2 , x2 = 8 and y1 = 9 , y2 = 6

∴ $\frac{y-9}{x-2}=\frac{6-9}{8-2}$

∴ $\frac{y-9}{x-2}=\frac{-3}{6}======\frac{y-9}{x-2}=\frac{-1}{2}$

- By using cross multiplication

∴ 2(y - 9) = -1(x - 2) ⇒ simplify

∴ 2y - 18 = -x + 2 ⇒ add x and 18 for two sides

∴ x + 2y = 20 ⇒ (5)

- Equations (1) and (5) are the same

∴ The 1st and the 5th tables represent the same function

3 0

3 years ago

Solve the equation.-21=m/3m m=7 m=-7 m=-63 m=63