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yuradex [85]
3 years ago
9

If f(x) = x2 – 3 and g(x) = 4x +3, then f(g(2)) =

Mathematics
1 answer:
WARRIOR [948]3 years ago
8 0

Answer:

4*+1

Step-by-step explanation:

To find

g

(

f

(

x

)

)

you must substitute

f

(

x

)

or

4

x

+

3

for each occurrence of

x

in

g

(

x

)

.

g

(

x

)

=

x

−

2

becomes:

g

(

f

(

x

)

)

=

(

4

x

+

3

)

−

2

g

(

f

(

x

)

)

=

4

x

+

3

−

2

g

(

f

(

x

)

)

=

4

x

+

1

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What’s the correct answer ???
Svetlanka [38]
The correct answer is the second one
7 0
3 years ago
29 If the zeros of a quadratic function, F, are -3 and 5, what is the equation of the axis of symmetry
UNO [17]

Answer:

the axis of symmetry is X = 1

Step-by-step explanation:

make sure to ask if you need any further guidance.

8 0
1 year ago
Write an inequality for the graph shown below.<br> User for your variable.<br> X<br> o<br> ?
zvonat [6]

Answer:

3 > x

Step-by-step explanation:

3 is larger than all of the values on the line, of which the arrow is pointing. The circle is open, so it means that it is not greater than or equal to.

I hope this helps!

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8 0
2 years ago
The augmented matrix of a system of equations has been transformed to an equivalent matrix in​ row-echelon form. Using​ x, y
jenyasd209 [6]

Answer: The system of equations is:

x + 2y + 2 = 4

y - 3z = 9

z = - 2

The solution is: x = -22; y = 15; z = -2;

Step-by-step explanation: ONe way of solving a system of equations is using the Gauss-Jordan Elimination.

The method consists in transforming the system into an augmented matrix, which is writing the system in form of a matrix and then into a <u>Row</u> <u>Echelon</u> <u>Form,</u> which satisfies the following conditions:

  • There is a row of all zeros at the bottom of the matrix;
  • The first non-zero element of any row is 1, which called leading role;
  • The leading row of the first row is to the right of the leading role of the previous row;

For this question, the matrix is a Row Echelon Form and is written as:

\left[\begin{array}{ccc}1&2&2\\0&1&3\\0&0&1\end{array}\right]\left[\begin{array}{ccc}4\\9\\-2\end{array}\right]

or in system form:

x + 2y + 2z = 4

       y + 3z = 9

               z = -2

Now, to determine the variables:

z = -2

y + 3(-2) = 9

y = 15

x + 30 - 4 = 4

x = - 22

The solution is (-22,15,-2).

4 0
3 years ago
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