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Sophie [7]
3 years ago
6

Determine the molar solubility of AgBr in a solution containing 0.150 M NaBr. Ksp (AgBr) = 7.7 Ă— 10-13. Determine the molar sol

ubility of AgBr in a solution containing 0.150 M NaBr. Ksp (AgBr) = 7.7 Ă— 10-13. 5.1 Ă— 10-12 M 3.9 Ă— 10-13 M 0.150 M 5.8 Ă— 10-5 M 8.8 Ă— 10-7 M
Chemistry
1 answer:
Kaylis [27]3 years ago
5 0

Hey there!:

Given the reaction:

 NaBr  ⇌  Na⁺ +  Br⁻

  ↓              ↓         ↓

0.150M      0.150M     0.150M


AgBr ⇌ Ag⁺   + Br⁻

 ↓            ↓          ↓

 x            x         0.150M


Therefore:

Ksp = x * 0.150

x = ( 7.7 * 10⁻¹³ ) / 0.150

x = 5.1 * 10⁻¹²


Answer B


Hope that helps!

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Answer:

D

Explanation:

6 0
3 years ago
A
BARSIC [14]

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The number of SO_2 molecules in 9.87 moles  SO_2 is 59.43 molecules.

The moles of Fe in 1.40 x 10^{22} atoms of Fe is 0.23 x 10^{-1}

The moles of C_2H_6O in 2.30x10^{24} molecules of C_2H_6O is 3.81.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

A. The number of C atoms in 0.524 mole of C:

6.02214076 × 10^{23} x 0.524 mole

3.155601758 atoms =3.155 atoms

B. The number of SO_2 molecules in 9.87 moles of SO_2:

6.02214076 × 10^{23} x 9.87

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1.40 x 10^{22} ÷ 6.02214076 × 10^{23}

0.2324754694 x 10^{-1} moles.

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2.30x10^{24} ÷ 6.02214076 × 10^{23}

3.819239854 moles=3.81 moles

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

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2 years ago
Can someone help me with this please
never [62]

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