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Aleks [24]
4 years ago
11

What is the relationship between a problem statement and the hypothesis?

Chemistry
1 answer:
dlinn [17]4 years ago
3 0
An hypothesis is the proposed explanation that is made on the basis of limited evidence and it serves as the starting point for further investigation while a problem statement is a clear, concise description of the problems which needs to be addressed. 
Problem statement is used to concentrate the focus of the researcher at the beginning, to keep him on track during the operation  and at the end it is used to evaluate if the process delivered an outcome that solve the problems.
Hypothesis is used to define the relationship between two variables at the end of the research the scientist has to decide when its starting hypothesis is valid or not.<span />
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Answer question 1-6
Softa [21]
It is 4 because if you think about it it makes more sense
7 0
3 years ago
How many HCL-molecules in 1,5mol HCL
Vera_Pavlovna [14]

Answer:

number of molecules =9.03×10^23

Explanation:

use the equation

n=number of molecules /Av.constant

make number of Molecules become the subject of the formula by multplying Av.constant on both sides of the equation,

number of molecules=n×Av. constant ,where Av.constant is 6.02×10^23

number of molecules=1.5mol×6.02×10^23

=9.03×10^23

3 0
3 years ago
How many atoms are in NH₄C₂H₃O₂? Sorry, I'm confused because there are two "H"s: H₄ and H₃. Please explain if this would just be
krek1111 [17]

Answer:

11

Explanation:

NH=4

C=2

H=3

O=2

4 0
3 years ago
1. which volume has the most uncertainty associated wit the measurement?
Mamont248 [21]
1. The option a. 10 mL has the most uncertainty associated with it, because it has only 2 significative figures, while 10.0 mL has three significant figures and 10.00 has four significant figures.

2. The volume of solution that remains is 145.675 mL - 24.2 mL = 121.475 mL rounded to one decimal  = 121.5 mL, given that the measure with the most uncerntainty has only one decimal.
 

 
4 0
4 years ago
How many grams of CuSO4 • 5H2O do you need to make 0.8 L of a 0.6 M solution
Bumek [7]
<h3><u>Unders</u><u>tanding</u><u> </u><u>the</u><u> </u><u>conc</u><u>ept</u><u>:</u><u>-</u></h3>

Here the concept of Molarity used .We will put the formula of Molarity then we find moles of copper sulphate .Then we can find the.Given weight of Copper sulphate.So let's do

<h3>Solution:-</h3>

  • Volume of Solvent=0.8L
  • Molarity=0.6M

We know

\boxed{\sf Molarity=\dfrac{Moles\:of\: solute}{Volume\:of\: Solvent \:in\;L}}

\\ \rm\longmapsto Moles\:of\: solute=Molarity\times Volume\:of\: Solvent\:in\:L

\\ \rm\longmapsto Moles\:of\: Solute=0.8(0.6)

\\ \rm\longmapsto Moles\:of\: Solute=0.48mol

Now

Molar Mass of Solute:-

\\ \rm\longmapsto CuSO_4.5H_2O

\\ \rm\longmapsto 65u+32u+4(16u)+5(2\times 1u+16u)

\\ \rm\longmapsto 96u+64u+5(2+16)

\\ \rm\longmapsto 160u+90u

\\ \rm\longmapsto 250u

\\ \rm\longmapsto 250g/mol

Now

\boxed{\sf No\:of\:moles=\dfrac{Given\:Mass}{Molar\:Mass}}

\\ \rm\longmapsto Given\:Mass=No\:of\:Moles\times Molar\:Mass

\\ \rm\longmapsto Given\:Mass=250(0.48)

\\ \rm\longmapsto Given\:Mass=120g

8 0
3 years ago
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