Points

Fe(II) can be precipitated from a slightly basic aqueous solution by bubbling oxygen through the solution, which converts Fe(II)

vovangra [49]

Answer:

0,051g of O₂

Explanation:

The reaction of precipitation of Fe is:

4Fe(OH)⁺(aq) + 4OH⁻(aq) + O₂(g) + 2H₂O(l) → 4Fe(OH)₃(s)

-Where the Fe(OH)⁺ is Fe(II) and Fe(OH)₃ is Fe(III)-

This reaction is showing you need 1 mol of O₂(g) per 4 moles of Fe(II) for a complete reaction.

85mL= 0,085L of 0,075M Fe(II) are:

0,085L*0,075M = 6,34x10⁻³ moles of Fe(II)

For a complete reaction of 6,34x10⁻³ moles of Fe(II) you need:

6,34x10⁻³ moles of Fe(II)× $\frac{1molO_2}{4moles Fe(II)}$ =

1.59x10⁻³ moles of O₂. In grams:

1.59x10⁻³ moles of O₂× $\frac{32g}{1molO_2}$ = 0,051g of O₂

I hope it helps!

7 0

3 years ago

What are the magnitude (size) and direction of the cumulative force acting on the car shown in the picture A. 30 N to the right

UNO [17]

Answer: The correct answer is option(A).

Explanation:

Total forces exerting on the car = F

$F_r=50 N$ = Force on car exerting in right direction

$F_l=20 N$ = Force on car exerting in left direction

$F_u=2500 N$ = Force on car exerting in upward direction

$F_d=2500 N$ = Force on car exerting in downward direction

$F=F_r+F_l+F_u+F_d$

$(-F_u)=F_d$ (negative sign shows the direction)

Since, upward force are equal in magnitude but opposite in direction by which they will balance out each other.so, the net force car will be due to two forces $F_r$ and $F_l$

$F=F_r+F_l=50 N+(-20 N)=30 N$ (negative shows the direction)

The magnitude (size) and direction of the cumulative force acting on the car will 30 N towards right direction.Hence, correct answer is option(A).

4 0

3 years ago

Read 2 more answers

use the periodic table to select the element from the drop-down menu that has the correct relative electronegativity.

Bumek [7]

You need to list the elements but remember that fluorine has the highest electronegativity out of the entire periodic table

6 0

3 years ago

Read 2 more answers

Given the following reaction:

Wewaii [24]

Answer:

Approx. 4⋅g.

Explanation:

Moles of sulfuric acid =10.0⋅g98.08⋅g⋅mol−1=0.102⋅mol.

Now we have the molar quantity of sulfuric acid that react; we also have the stoichiometric equation that shows the molar equivalence of sulfuric acid, and lithium hydroxide.

Given the stoichiometry,

mass of water =0.102⋅mol×2×18.01.g.mol−1=??⋅g.

Why did I multiply the mass in this equation by 2? Am I pulling your leg?

3 0

2 years ago

The combustion of ammonia in the presence of excess oxygen yields no2 and h2o: 4 nh3 (g) + 7 o2 (g) â 4 no2 (g) + 6 h2o (g) the

VLD [36.1K]

The answer would be 118.68 g.
Explanation for this is:4 moles of NH3 give 4 moles of NO2
so 1mole of NH3 will give 1 mole of NO2
43.9 grams of NH3 contains 2.58 moles
so 2.58 moles will be produced of NO2
which is 118.7 grams this the amount of oxygen that is used.

8 0

3 years ago