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dimulka [17.4K]
3 years ago
10

If 1.25L of gas exists at 35∘C with a constant pressure of 0.70 atm in a cylindrical block and the volume were to be changed to

0.75L, what is the new temperature of the gas?
Chemistry
1 answer:
Vlad [161]3 years ago
7 0

Answer:

hey are related by the the density triangle.

Explanation:

They are related by the the density triangle.

mcdn1.teacherspayteachers.com

d =  

m

V

m = d×V

V =  

m

d

DENSITY

Density is defined as mass per unit volume.

d =  

m

V

Example:

A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?

Step 1: Calculate the volume

V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³

Step 2: Calculate the density

d =  

m

V

=  

433

g

200

c

m

³

= 2.16 g/cm³

MASS

d =  

m

V

We can rearrange this to get the expression for the mass.

m = d×V

Example:

If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?

m = d×V = 500 mL ×  

1.11

g

1

m

L

= 555 g

VOLUME

d =  

m

V

We can rearrange this to get the expression for the volume.

V =  

m

d

Example:

What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.

Step 1: Convert kilograms to grams.

14.83 kg ×  

1000

g

1

k

g

= 14 830 g

Step 2: Calculate the volume.

V =  

m

d

= 14 830 g ×  

1

c

m

³

19.32

g

= 767.6 cm³

Explanation:

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PLEASE HELP
LenaWriter [7]

Hello!


I don't know a lot of this but after doing just a bit of research I think the answer is either A. or C. but I think it is A.


Hope it helps?

5 0
3 years ago
The average propane cylinder for a residential grill holds approximately 18 kg of propane. how much energy (in kj) is released b
Angelina_Jolie [31]
Let's begin with the basic values  that will be used in the solution.

The formula of propane is C3H8. It is an alkane, a hydrocarbon with the general formula of CnH2n+2. Notice that hydrocarbons have only Carbon and Hydrogen atoms. Its molar mass (M) is 44 g.

Molar Mass Calculation is done as like that
C=12 g/mol, H=1 g/mol. 1 mole propane has 3 moles Carbon atoms and 8 mole Hydrogen atoms. M(
C3H8)= 3*12+ 8*1= 44 g

Combustion reaction of hydrocarbons gives carbon dioxide and water by releasing energy. That energy is called as enthalpy of combustion (
ΔHc°).  

ΔHc° of propane equals -2202.0 kj/mol. Burning of 1 mole C3H8 releases 2202 kj energy. Minus sign only indicates that the energy is given out ( an exothermic reaction ).

Let's write the combustion reaction.
C3H8 + O2 ---> CO2 + H20 (unbalanced) 
ΔHc° = -2202 kj/mol

Now, we calculate mole of 20 kg propane. Convert kilogram into gram since we use molar mass is defined in grams.
mole=mass/molar mass ; n=m/M ; n= 20000 g /44 (g/mol)=454 mole

1 mole propane releases 2202 kj energy.
454 mole propane release 2202 kj *454= 1000909 kj

The answer is 1000909 kj.



6 0
4 years ago
In what way does ocean water move globally?
Vikki [24]

Answer:

A. Along warm-water currents from warmer regions to colder regions

\

Explanation:

8 0
2 years ago
Read 2 more answers
When 1.5 grams of magnesium burns, how many grams of magnesium oxide will be formed?
SashulF [63]
The balanced chemical reaction for this would be written as:

2Mg + O2 = 2MgO

We use this reaction and the amount of the reactant given to calculate for the amount of magnesium oxide that is produced. We do as follows:

1.5 g Mg (1 mol / 24.31 g) ( 2 mol MgO / 2 mol Mg ) (40.30 g /1 mol ) = 2.49 g MgO produced
6 0
3 years ago
A reaction mixture at equilibrium at 175 k contains ph2 = 0.958 atm, pi2 = 0.877 atm, and phi = 0.020 atm. a second reaction mix
Sophie [7]
 from ICE table
            H2(g) +  I2 (g )↔ 2HI(g)
 equ       0.958      0.877         0.02   first mix1
              0.621        0.621         0.101      sec mix2

Kp1 = P(HI)^2 / p(H2)*p(I2) for mix 1
       = 0.02^2 / 0.958*0.877
       = 4.8x10^-4
Kp2 = P(HI)^2 / P(H2)* P(I2) for mix 2
        = 0.101^2/ 0.621*0.621 
        = 0.0265
we can see that Kp1< Kp2 that means that the sec mixture is not at equilibrium. It will go left to reduce its products and increase reactant to reduce the Kp value to achieve equilibrium.

and the partial pressure of Hi when mix 2 reach equilibrium is:
4.8x10^-4 = P(Hi)^2 / (0.621*0.621)
∴ P(Hi) at equilibrium = 0.0136 atm



8 0
3 years ago
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