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REY [17]
2 years ago
6

In what way does ocean water move globally?

Chemistry
2 answers:
Vikki [24]2 years ago
8 0

Answer:

A. Along warm-water currents from warmer regions to colder regions

\

Explanation:

Lena [83]2 years ago
8 0
A because I did it already
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Water has a vapor pressure of 23.8 mm Hg at 25°C and a heat of vaporization of 40.657 kJ/mol. Using the Clausius-Clapeyron equat
zubka84 [21]

Answer:

P = 559.553 mmHg

Explanation:

Clasius-Clapeyron:

  • Ln(P2/P1) = - ΔHv/R [ 1/T2 - 1/T1 ]

∴ P1 = 23.8 mmHg = 3.173 KPa

∴ T1 = 25°C ≅ 298 K

∴ ΔHv = 40.657 KJ/mol

∴ R = 8.314 E-3 KJ/K.mol

∴ T2 = 96°C ≅ 369 K

⇒ Ln P2/P1 = - (40.657 KJ/mol/8.314 E-3 KJ/K,mol) [(1/369 K) - (1/298 K) ]

⇒ Ln P2/P1 = - (4890.185 K) [ - 6.457 E-4 K-1 ]

⇒ Ln P2/P1 = 3.1575

⇒ P2/P1 = 23.511

⇒ P2 = (23.511)(3.173 KPa)

⇒ P2 = 74.601 KPa = 559.553 mmHg

6 0
3 years ago
Which of the following statements are true of acids and bases?
gtnhenbr [62]
A. Acids increase the number of OH- ions in a solution. FALSE
B. Bases increase the number of OH- ions in a solution. TRUE
C. Acids increase the number of H+ ions in a solution. TRUE
D. Bases increase the number of H+ ions in a solution. FALSE
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3 years ago
What’s the amino acid for this?
Pachacha [2.7K]
The amino acid for this should be Arginine. I am not entirely sure.
5 0
2 years ago
When all parts of a circuit are composed of conducting materials, the circuit is said to
natima [27]
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8 0
4 years ago
Perform the following conversions:
jek_recluse [69]

Answer :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

^oC=\frac{5}{9}\times (^oF-32)

The conversion used for the temperature from degree Celsius to Kelvin is:

K=^oC+273

(a) 1.06^oF

^oC=\frac{5}{9}\times (^oF-32)

^oC=\frac{5}{9}\times (1.06^oF-32)

^oC=-17.188

The temperature in degree Celsius is, -17.188^oC

K=^oC+273

K=-17.188+273

K=255.812

The temperature in Kelvin is, 255.812 K

(b) 3410^oC

^oC=\frac{5}{9}\times (^oF-32)

3410^oC=\frac{5}{9}\times (^oF-32)

^oF=6106

The temperature in degree Fahrenheit is, 6106^oF

K=^oC+273

K=3410+273

K=3683

The temperature in Kelvin is, 3683 K

(c) 6.1\times 10^3K

K=^oC+273

6.1\times 10^3K=^oC+273

^oC=5827

The temperature in degree Celsius is, 5827^oC

^oC=\frac{5}{9}\times (^oF-32)

5827^oC=\frac{5}{9}\times (^oF-32)

^oF=10456.6

The temperature in degree Fahrenheit is, 10456.6^oF

8 0
3 years ago
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