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Mandarinka [93]
4 years ago
6

The average propane cylinder for a residential grill holds approximately 18 kg of propane. how much energy (in kj) is released b

y the combustion of 20.00 kilograms of propane in sufficient oxygen?
Chemistry
1 answer:
Angelina_Jolie [31]4 years ago
6 0
Let's begin with the basic values  that will be used in the solution.

The formula of propane is C3H8. It is an alkane, a hydrocarbon with the general formula of CnH2n+2. Notice that hydrocarbons have only Carbon and Hydrogen atoms. Its molar mass (M) is 44 g.

Molar Mass Calculation is done as like that
C=12 g/mol, H=1 g/mol. 1 mole propane has 3 moles Carbon atoms and 8 mole Hydrogen atoms. M(
C3H8)= 3*12+ 8*1= 44 g

Combustion reaction of hydrocarbons gives carbon dioxide and water by releasing energy. That energy is called as enthalpy of combustion (
ΔHc°).  

ΔHc° of propane equals -2202.0 kj/mol. Burning of 1 mole C3H8 releases 2202 kj energy. Minus sign only indicates that the energy is given out ( an exothermic reaction ).

Let's write the combustion reaction.
C3H8 + O2 ---> CO2 + H20 (unbalanced) 
ΔHc° = -2202 kj/mol

Now, we calculate mole of 20 kg propane. Convert kilogram into gram since we use molar mass is defined in grams.
mole=mass/molar mass ; n=m/M ; n= 20000 g /44 (g/mol)=454 mole

1 mole propane releases 2202 kj energy.
454 mole propane release 2202 kj *454= 1000909 kj

The answer is 1000909 kj.



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The wavelength of a particular color of violet light is 433 nm. The energy of this wavelength of light is kJ/photon. (109 nm = 1
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4.59 × 10⁻³⁶ kJ/photon

Explanation:

Step 1: Given and required data

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  • Speed of light (c): 3.00 × 10⁸ m/s

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433 nm × 1 m/10⁹ nm = 4.33 × 10⁷ m

Step 3: Calculate the energy (E) of the photon

We will use the Planck-Einstein's relation.

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Answer: 1.87 atm

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Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

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V_1 = initial volume of gas = 26.4 ml

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T_1 = initial temperature of gas = 2.5^oC=273+2.5=275.5K

T_2 = final temperature of gas = 10^oC=273+10=283K

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\frac{2.50\times 26.4}{275.5}=\frac{P_2\times 36.2}{283}

P_2=1.87atm

The new pressure is 1.87 atm by using combined gas law.

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