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Mandarinka [93]
3 years ago
6

The average propane cylinder for a residential grill holds approximately 18 kg of propane. how much energy (in kj) is released b

y the combustion of 20.00 kilograms of propane in sufficient oxygen?
Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
6 0
Let's begin with the basic values  that will be used in the solution.

The formula of propane is C3H8. It is an alkane, a hydrocarbon with the general formula of CnH2n+2. Notice that hydrocarbons have only Carbon and Hydrogen atoms. Its molar mass (M) is 44 g.

Molar Mass Calculation is done as like that
C=12 g/mol, H=1 g/mol. 1 mole propane has 3 moles Carbon atoms and 8 mole Hydrogen atoms. M(
C3H8)= 3*12+ 8*1= 44 g

Combustion reaction of hydrocarbons gives carbon dioxide and water by releasing energy. That energy is called as enthalpy of combustion (
ΔHc°).  

ΔHc° of propane equals -2202.0 kj/mol. Burning of 1 mole C3H8 releases 2202 kj energy. Minus sign only indicates that the energy is given out ( an exothermic reaction ).

Let's write the combustion reaction.
C3H8 + O2 ---> CO2 + H20 (unbalanced) 
ΔHc° = -2202 kj/mol

Now, we calculate mole of 20 kg propane. Convert kilogram into gram since we use molar mass is defined in grams.
mole=mass/molar mass ; n=m/M ; n= 20000 g /44 (g/mol)=454 mole

1 mole propane releases 2202 kj energy.
454 mole propane release 2202 kj *454= 1000909 kj

The answer is 1000909 kj.



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24. a, combination reaction. There are two reactants and one product.
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Answer:

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3 years ago
How many hours will it take for the concentration of methyl isonitrile to drop to 14.0 %% of its initial value?
tiny-mole [99]

This is an incomplete question, here is a complete question.

The rearrangement of methyl isonitrile (CH₃NC) to acetonitrile (CH₃NC) is a first-order reaction and has a rate constant of 5.11 × 10⁻⁵ s⁻¹ at 472 K. If the initial concentration of CH₃NC is 3.00 × 10⁻² M :

How many hours will it take for the concentration of methyl isonitrile to drop to 14.0 % of its initial value?

Answer : The time taken will be, 10.7 hours

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 5.11\times 10^{-5}s^{-1}

t = time passed by the sample  = ?

a = let initial amount of the reactant  = 100

a - x = amount left after decay process = 14 % of 100 = 14

Now put all the given values in above equation, we get

t=\frac{2.303}{5.11\times 10^{-5}}\log\frac{100}{14}

t=38482.72s=\frac{38482.72}{3600}=10.7hr

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7 0
3 years ago
Calculate the mass in grams of carbon needed to produce 160 g of CO2 in burning: C + O2 --&gt; CO2
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5 0
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the developing chamber is not covered with plastic wrap during the development of the chromatogram. will the Dion value for the
kogti [31]

Answer:

The correct answer is less than the actual value.

Explanation:

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Have a nice day!

8 0
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