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musickatia [10]
4 years ago
10

How is the temperature of the Earth's atmosphere linked to the concentration of carbon dioxide?

Chemistry
2 answers:
Anni [7]4 years ago
7 0

Answer:

the amount of carbon dioxide controls the earths temperature

Explanation:

that is why global warming is a problem because the more carbon dioxide produced the hotter earth gets

Tresset [83]4 years ago
5 0
Carbon dioxide produces heat
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This is 20 points!!!
Ann [662]

Answer:

I think it both physical & chemical change :')

5 0
2 years ago
How many sulfur atoms are present in 25.6 g of Al2(S2O3)3
IgorC [24]

Given the mass of Al_{2}(S_{2}O_{3})_{3}=25.6 g

The molar mass of Al_{2}(S_{2}O_{3})_{3}=390.35g/mol

Converting mass of Al_{2}(S_{2}O_{3})_{3}to moles:

25.6 g Al_{2}(S_{2}O_{3})_{3}*\frac{1molAl_{2}(S_{2}O_{3}}{390.35 gAl_{2}(S_{2}O_{3}} =0.0656molAl_{2}(S_{2}O_{3}

Converting mol Al_{2}(S_{2}O_{3})_{3}to mol S:

0.0656mol Al_{2}(S_{2}O_{3})_{3}*\frac{6molS}{1mol Al_{2}(S_{2}O_{3})_{3}}=0.3936 molS

Converting mol S to atoms of S using Avogadro's number:

1 mol = 6.022*10^{23}atoms

0.3936mol S *\frac{6.022*10^{23}atoms S}{1 mol S}=2.37*10^{23} S atoms

5 0
3 years ago
Which of the following is the best example of an open system? (2 points)
Dmitriy789 [7]
1) A Car engine.............. Hope it helps, Have a nice day :)
5 0
3 years ago
Read 2 more answers
How many carbon atoms are there in a 1.3-carat diamond? diamonds are a form of pure carbon. (1 carat?
Colt1911 [192]
How many carbon atoms are there in a 1.3-carat diamond? Answer: 1.3 x 10^22 C atoms...
If a 1 carat = 0.20 g ... then 0.3 carat = 0.20 / 0.3 = 0.06 g
Thus, 1.3 carat = 0.26g
Find the moles first:
Moles= Grams / Mm of C
0.26 / 12.011 = 0.0216 mols of C
Atoms = Moles * Avogadro's number (6.022*10^23)
0.0216 * 6.022*10^23 = 1.3*10^22 C atoms

Hope this helps! :)
8 0
3 years ago
Read 2 more answers
By weight atmospheric air is approximately 23.15% oxygen and 76.85% nitrogen. What is the partial pressure of oxygen in the air
inna [77]

Answer:

Partial pressure of oxygen = 23.38 kpa (Approx)

Explanation:

Given:

Amount of oxygen = 23.15%

Amount of nitrogen = 76.85%

Pressure (missing) = 101 kpa

Find:

Partial pressure of oxygen

Computation:

Partial pressure of oxygen = [Amount of oxygen x Pressure]/100

Partial pressure of oxygen = [23.15% x 101]/100

Partial pressure of oxygen = 23.38 kpa (Approx)

5 0
3 years ago
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