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Schach [20]
3 years ago
6

4 2/5x=12 1/12 (Can You Help Me Please)

Mathematics
1 answer:
vaieri [72.5K]3 years ago
7 0

Hello.

The answer is: 2 3/4

Step 1: Simplify both sides of the equation.

22/5x 121/10

Step 2: Multiply both sides by 5/22.

(5/22)* (22/5 x)= (5/22)* (121/10)

Have a nice day

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The temp at noon was 3*F and in midnight the temp dropped 8*F. What was the temp at midnight?
Romashka [77]

Answer: -5°F

Step-by-step explanation:

The temp at noon was 3*F and in midnight the temp dropped 8*F. Therefore, the temp at midnight will be calculated as:

= 3°F - 8°F.

= -5°F

6 0
3 years ago
Simplify 1/2(8-4g) pls help me
muminat

Answer:

2(-g+2)

Step-by-step explanation

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3 years ago
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A government agency has specialists who analyze the frequencies of letters of the alphabet in an attempt to decipher intercepted
mylen [45]

let n be the number of times letter be found (1800), p be the success rate (0.068), and q be the failure rate (1 - 0.068 = 0.932)  

mean = np = 1800 x 0.068 = 122.4  

standard deviation = √(npq) = √(1800 x 0.068 x 0.932) = 10.6807414

4 0
3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
Factor completely: 2x3 + 6x2 + 10x + 30
qwelly [4]
The complete factor from:

2x3 + 6x2 + 10x + 30
2x(x+3) + 10(x+3)
(x+3)(2x+10)
2(x+5)(x+3)

hope this help
3 0
3 years ago
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