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3 years ago

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Puzzles are packaged in groups of 3. If the store has 183 nature puzzles and 165 animal puzzles, how many packages of puzzles ar

e there?

1 answer:

Yuri [45]3 years ago

5 0

Answer: 116 packages

Step-by-step explanation:

From the question, we are informed that Puzzles are packaged in groups of 3 and that the store has 183 nature puzzles. The number of packages here will be:

= 183/3

= 61 packages

For the 165 animal puzzles, the number of packages will be:

= 165/3

= 55 packages

The total number of packages of puzzles will be:

= 61 + 55 packages

= 116 packages

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Dada la sucesión an = 1700 + 4,1· n2 + 304,9· n

shutvik [7]

Concluimos que la opción correcta es <em>"Solo II"</em>.

Una expresión es una sucesión aritmética si y solo si existe entre dos elementos <em>consecutivos</em> cualesquiera de la serie la misma diferencia. La sucesión aritmética es definida por una expresión de la forma:

$a_{n} = a + b\cdot n$ , $n\in \mathbb{N}$ (1)

Donde $a,b$ son coeficientes de la sucesión.

Asimismo, una expresión es una sucesión geométrica si y solo si entre dos elementos <em>consecutivos</em> cualesquiera de la serie existe la misma razón. La sucesión geométrica es definida por una expresión de la forma:

$a_{n} = a\cdot r^{b\cdot n}$ , $n\in \mathbb{N}$ (2)

Donde $a, b, r$ son coeficientes de la sucesión.

Por último, una expresión es una sucesión monótona creciente si dados dos elementos <em>consecutivos</em> de una serie, el elemento posterior es siempre mayor que el elemento anterior. Matemáticamente, debe satisfacerse la siguiente condición:

$\frac{a_{n+1}}{a_{n}} > 1, n\in \mathbb{N}$ (3)

Esta claro por inspección directa que la sucesión dada no es aritmética ni geométrica y cabe comprobar si es monótona creciente. Valiéndonos de (3), realizamos las operaciones algebraicas pertinentes:

$r = \frac{1700 + 4,1\cdot (n+1)^{2}+304,9\cdot (n+1)}{1700 + 4,1\cdot n^{2}+304,9\cdot n}$

$r = \frac{1700+4,1\cdot (n^{2}+2\cdot n +1) +304,9\cdot (n+1)}{1700 + 4.1\cdot n^{2}+304,9\cdot n}$

$r = \frac{1700+4,1\cdot n^{2}+304,9\cdot n+4,1\dot (2\cdot n +1) +304.9}{1700+4,1\cdot n^{2}+304,9\cdot n}$

$r = 1 + \frac{8,2\cdot n +309}{1700 + 4,1\cdot n^{2}+304,9\cdot n}$

Como puede apreciarse, $r > 1$ . Por tanto, la sucesión es monótona y creciente.

En consecuencia, concluimos que la opción correcta es <em>"Solo II"</em>.

Invitamos cordialmente a leer esta pregunta sobre sucesiones: brainly.com/question/21709418

4 0

3 years ago

Kerry invests $682 in a savings account that earns 5.4% compounded annually. Andy invests $682 in a savings account that earns 7

mylen [45]

1050.28 Kerry’s money (10years later)
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3 years ago

Find the derivative of following function.

Aleks04 [339]

Answer:

$\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \tan^2 x + 5x \big) + \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( 2 \sec^2 x \tan x + 5 \big)}{ \big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)} + \frac{2 \cot x \csc^2 x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2 \big( \sin^2x + 6 \big)} - \frac{2 \cos x \sin x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)^2}$

General Formulas and Concepts:
<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle (cu)' = cu'$

Derivative Property [Addition/Subtraction]:
$\displaystyle (u + v)' = u' + v'$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:
$\displaystyle (uv)' = u'v + uv'$

Derivative Rule [Quotient Rule]:
$\displaystyle \bigg( \frac{u}{v} \bigg)' = \frac{vu' - uv'}{v^2}$

Derivative Rule [Chain Rule]:
$\displaystyle [u(v)]' = u'(v)v'$

Step-by-step explanation:

*Note:

Since the answering box is <em>way</em> too small for this problem, there will be limited explanation.

<u>Step 1: Define</u>

<em>Identify.</em>

$\displaystyle y = \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \times \frac{\tan^2 x + 5x}{\csc^2 x + 3}$

<u>Step 2: Differentiate</u>

We can differentiate this function with the use of the given <em>derivative rules and properties</em>.

Applying Product Rule:

$\displaystyle y' = \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' \frac{\tan^2 x + 5x}{\csc^2 x + 3} + \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) '$

Differentiating the first portion using Quotient Rule:

$\displaystyle \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' = \frac{\big( \cos^2 x - 3\sqrt{x} + 6 \big)' \big( \sin^2 x + 6 \big) - \big( \sin^2 x + 6 \big)' \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2}$

Apply Derivative Rules and Properties, namely the Chain Rule:

$\displaystyle \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - \big( 2 \sin x \cos x \big) \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2}$

Differentiating the second portion using Quotient Rule again:

$\displaystyle \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) ' = \frac{\big( \tan^2 x + 5x \big)' \big( \csc^2 x + 3 \big) - \big( \csc^2 x + 3 \big)' \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}$

Apply Derivative Rules and Properties, namely the Chain Rule again:
$\displaystyle \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) ' = \frac{\big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) - \big( -2 \csc^2 x \cot x \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}$

Substitute in derivatives:

$\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - \big( 2 \sin x \cos x \big) \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2} \frac{\tan^2 x + 5x}{\csc^2 x + 3} + \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \frac{\big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) - \big( -2 \csc^2 x \cot x \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}$

Simplify:

$\displaystyle y' = \frac{\big( \tan^2 x + 5x \big) \bigg[ \big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - 2 \sin x \cos x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \bigg]}{\big( \sin^2 x + 6 \big)^2 \big( \csc^2 x + 3 \big)} + \frac{\big( \cos^2 x - 3\sqrt{x} +6 \big) \bigg[ \big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) + 2 \csc^2 x \cot x \big( \tan^2 x + 5x \big) \bigg] }{\big( \csc^2 x + 3 \big)^2 \big( \sin^2 x + 6 \big)}$

We can rewrite the differential by factoring and common mathematical properties to obtain our final answer:

$\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \tan^2 x + 5x \big) + \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( 2 \sec^2 x \tan x + 5 \big)}{ \big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)} + \frac{2 \cot x \csc^2 x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2 \big( \sin^2x + 6 \big)} - \frac{2 \cos x \sin x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)^2}$

∴ we have found our derivative.

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Learn more about derivatives: brainly.com/question/26836290

Learn more about calculus: brainly.com/question/23558817

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Topic: Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

8 0

2 years ago

Read 2 more answers

The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is four times

prohojiy [21]

Answer:

{36, 66, 78}

Step-by-step explanation:

Let the measures of the three angles be f, s and t, for first, second and third. Then s + t = 4f, t = 12 + s, and f + s + t = 180.

Subbing 12 + s for t in the first equation, we get s + 12 + s = 4f.

Subbing the same in the third equation, we get f + s + 12 + s = 180

This results in two equations in two unknowns (f and s):

2s - 4f = -12

2s + f = 168.

Let's eliminate s by subtracting the first of these two equations from the second. Doing so yields 5f = 180. Then the first angle, f, or x, is 36.

Then, from 2s + f = 168, we get 2s + 36 = 168, or 2s = 132. Thus, the second angle is s = y = 66.

The sum of the three angles must be 180. Thus, 36 + 66 + t = 180, or

102 + t = 180, or t = z = 78.

The three angles are

{36, 66, 78}.

3 0

3 years ago

The first term of an arithmetic sequence is -2. The eighth term of the sequence is 26. What is the common difference of the arit

andreev551 [17]

Answer:

d = 4

Step-by-step explanation:

The n th term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₁ = - 2 and a₈ = 26 , then

- 2 + 7d = 26 ( add 2 to both sides (

7d = 28 ( divide both sides by 7 )

d = 4

8 0

3 years ago

Read 2 more answers